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Lynna [10]
4 years ago
9

In response to a body temperature above the set point, two effector responses in mammals could be _______ and _______.

Biology
2 answers:
loris [4]4 years ago
6 0
<span>In response to a body temperature above the set point, two effector responses in mammals could be sweating and panting. 

</span><span>Negative feedback stimulate activities of effectors (including sweat glands) that lower the temperature.</span>
ANEK [815]4 years ago
3 0

Answer:

In response to a body temperature above the set point, two effector responses in mammals could be sweating and panting.

Sweating and panting are two processes which are responsible for maintaining thermoregulation in the body. Thermoregulation maintains necessary heat energy in the body. Sweating is a process of removal of water from the body as a result of hot weather conditions. Loss of water occurs from skin. This water when comes in contact of air gives an affect of coolness, hence, keep the body cool in hot climate.

Panting is a process of loss of water in evaporation from the moist lining of the oral cavity and pharynx as a method of temperature regulation in the body.

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3 years ago
The bacteria grown in Luria broth with only lactose were expected to: Select one: a. Grow much faster than those grown in Luria
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The average radius of a molecule of lysozyme, and enzyme in tears, is 1430 pm. what is the radius in nanometers?
Galina-37 [17]

The average radius of a molecule of Iysozyme, an enzyme in tears, is 1430 pm.

The size of an element's nucleus and also the total number of electrons around it grow with an element's atomic number. The radius of an atom increases with increasing atomic number.

The calculation of conversion of radius is shown below:

It is known that, 1 meter is equal to 10¹² picometers.

We can use a conversion fraction to convert 1430 picometers to meters.

1430 pm × (1 m / 10¹² pm) = 1.430 × 10⁻⁹ m

1 meter is equal to 10⁹ nanometers.

Now, use a conversion fraction to convert 1.430 × 10⁻⁹ meters to nanometers.

1.430 × 10⁻⁹ m × (10⁹ nm/1 m) = 1.430 nm

Therefore, the radius of nanometers will be 1.430nm

To learn more about Average radius here

brainly.com/question/14499287

#SPJ4

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2 years ago
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