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4 years ago

Jean traveled the first 100 miles in 5 hours. Then she doubled her speed for the last part

Mathematics

2 answers:

denpristay [2]4 years ago

8 0

Answer:2hours and 30 minutes

Step-by-step explanation:If the first part of the trip(100miles) is 5hours. Then the second part of the trip( another 100miles) will be for 5hours too. The last part of the trip(the last 100miles to make up the 300 miles) will be for 2hours and 30 minutes since she doubled her speed for the last part of the trip.

Katyanochek1 [597]4 years ago

7 0

Time taken to travel the last part by Jean is 5 hours.

Step-by-step explanation:

Step 1: Given the total distance = 300 miles. Part 1 distance = 100 miles and time = 5 hours. Find speed for the first part.

⇒ Speed = Distance/Time = 100/5 = 20 miles/hour

Step 2: Find the speed of the second part given that she doubled her speed.

⇒ Speed for second part = 2 × 20 = 40 miles/hour

Step 3: Find the time taken to cover the last part by using the speed formula used above.

⇒ Time = Distance/Speed = 200/40 = 5 hours

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In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of

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The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

A line segment joining the mid-points of two sides in a triangle is parallel to the third side and equal to half its length

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = $\frac{1}{2}$ MN

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→ Multiply both sides by 2

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∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = $\frac{1}{2}$ MO

∵ KL = 13 units

∴ 13 = $\frac{1}{2}$ MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = $\frac{1}{2}$ ON

∵ ON =20 units

∴ JK = $\frac{1}{2}$ (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

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