U should be able to subtract off the plot but if not you have to trace them with invertables
Graph A is the correct answer
Good luck
Make into matrix
![\left[\begin{array}{ccc}2&1&1\\1&-3&-1\\4&5&2\end{array}\right] = \left[\begin{array}{ccc}-2\\14\\-4\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%261%261%5C%5C1%26-3%26-1%5C%5C4%265%262%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%5C%5C14%5C%5C-4%5Cend%7Barray%7D%5Cright%5D%20%20%20)
accoring to cramer's rule
replace the y collum with eh constant collumn and find the detterminant
![\left[\begin{array}{ccc}2&-2&1\\1&-14&-1\\4&-4&2\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-2%261%5C%5C1%26-14%26-1%5C%5C4%26-4%262%5Cend%7Barray%7D%5Cright%5D)
det
![2 \left[\begin{array}{ccc}14&-1\\-4&2\end{array}\right]-(-2) \left[\begin{array}{ccc}1&-1\\4&2\end{array}\right]+1 \left[\begin{array}{ccc}1&14\\4&-4\end{array}\right] ](https://tex.z-dn.net/?f=%202%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D14%26-1%5C%5C-4%262%5Cend%7Barray%7D%5Cright%5D-%28-2%29%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-1%5C%5C4%262%5Cend%7Barray%7D%5Cright%5D%2B1%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2614%5C%5C4%26-4%5Cend%7Barray%7D%5Cright%5D%20%0A%0A)
dunno wat fraction is
pick last option
The bisector of the angle at A (call it AQ) divides the segment BC into segments BQ:QC having the ratio AB:AC. Use this fact to find x.
.. 9:15 = (2x -1):3x
.. 15(2x -1) = 9*3x . . . . . the product of the means equals the product of extremes
.. 30x -15 = 27x
.. 3x = 15
.. x = 5
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According to the value of x, the bisector AQ divides the triangle into two isosceles triangles: ABQ, ACQ.