Put the other line in point slope form...(solve for y :D )
3y=15x+9
y=5x+3, so this line has a slope of 5
For a line to be perpendicular to another the slopes have to be negative reciprocals of each other...mathematically...
s1*s2=-1
So for the other line to be perpendicular to the first:
5m=-1, m=-1/5, thus our other line (so far) is:
y=b-x/5, now we can use the point (-8,-1) to solve for the y-intercept, "b":
-1=b-(-8)/5
-1=b+8/5
-1=b+1.6
b=-2.6
So the perpendicular line that contains the point (-8,-1) is:
y=-0.2x-2.6
39 is A
40 is D
And that is my answer
It is 2 :)
Y=A sin(B(x+C))+D
Where A is equal to the amplitude.
Would appreciate brainliest answer :)
<span>the expressions that are NOT polynomials
</span><span>A. x^2-(square root of x)-3
</span><span>C. 5x^1/2 + 4x^2
</span><span>E. x^2-x-12/x+3
(method: check polynomials lesson)</span>
Answer: r<-2
Step-by-step explanation:
-3(r-5)+7>28
-3(r-5)+7-7>28-7
-3(r-5)>21
3(r-5)/3 < -21/3
r-5<-7
r-5+5<-7+5
r<-2
