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Keith_Richards [23]
4 years ago
10

What is the following quotient? √96/√8

Mathematics
2 answers:
Kipish [7]4 years ago
7 0
Hope this helps. Might have a few extra steps.

inysia [295]4 years ago
4 0

Answer:

2\sqrt{3}

Step-by-step explanation:

We are asked to find the quotient of expression: \frac{\sqrt{96}}{\sqrt{8}}

Upon using the quotient rules for radicals we will get,  

\frac{\sqrt{96}}{\sqrt{8}} =\sqrt{\frac{96}{8}

Now let us cancel out GCF of 96 and 8.

\sqrt{\frac{96}{8}}=\sqrt{12}

Now let us factor out perfect square from \sqrt{12}

\sqrt{12}=\sqrt{4}\times\sqrt{3}

\sqrt{4}\times\sqrt{3}=2\sqrt{3}

Therefore, our radical expression simplifies to 2\sqrt{3}.

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Answer:

part A: Mean:6.42 Median:7

Part b: median

Part c: no it’s skewed left and unimodal

Step-by-step explanation:

3 0
3 years ago
Question in the picture
ehidna [41]

Answer:

y=2x+5 is the answer ALSO CAN WE TALK ABOUT THE FACT THAT MOO975 IS ON THREE QUESTIONS AT THE SAME TIME

Step-by-step explanation:

6 0
3 years ago
App 19.study
lions [1.4K]

Answer:

1 \to 22 \to 0.176

2 \to 13 \to 0.104

3 \to 18 \to 0.144

4 \to 29 \to 0.232

5 \to 37 \to 0.296

6 \to 6 \to 0.048

Step-by-step explanation:

Given

n = 125

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

Pr = \frac{Frequency}{n}

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

Pr(2) = \frac{13}{125} = 0.104

Pr(4) = \frac{29}{125} = 0.232

Pr(6) = \frac{6}{125} = 0.048

When the frequency is to be calculated, we use:

Pr = \frac{Frequency}{n}

Frequency = n * Pr

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

Frequency(3) = 125 * 0.144 = 18

Frequency(5) = 125 * 0.296 = 37

For roll of 1 where the frequency and the probability are not known, we use:

Total \ Frequency = 125

So:

Frequency(1) added to others must equal 125

This gives:

Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125

Frequency(1) + 103 = 125

Collect like terms

Frequency(1) =- 103 + 125

Frequency(1) =22

The probability is then calculated as:

Pr(1) = \frac{22}{125}

Pr(1) = 0.176

So, the complete table is:

1 \to 22 \to 0.176

2 \to 13 \to 0.104

3 \to 18 \to 0.144

4 \to 29 \to 0.232

5 \to 37 \to 0.296

6 \to 6 \to 0.048

5 0
3 years ago
Alma invests $300 in an account that compounds interest annually. After 2 years, the balance of the account is $329.49. To the n
-Dominant- [34]

Invested amount (P) = $300.

Time in years (t) = 2 years.

Balance after 2 years (A) = $329.49.

Let us assume rate of interest = r % compounds annually.

We know, formula for compound interest

A=P(1+r)^t

Plugging values in formula, we get

329.49=300(1+r)^2

\mathrm{Divide\:both\:sides\:by\:}300

\frac{300\left(1+r\right)^2}{300}=\frac{329.49}{300}

\left(1+r\right)^2=1.0983

Taking square root on both sides, we get

1+r=\sqrt{1.0983}

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+r-1=\sqrt{1.0983}-1

r=\sqrt{1.0983}-1

r=1.048-1

r=0.048.

Converting it into percentage by multiplying by 100.

r=0.048 × 100

r  = 4.8 %

Therefore, the rate of interest on the account is 4.8% compounds annually.

5 0
3 years ago
Ron finds 9 books at a bookstore that he would like to buy, but he can afford only 5 of them. In how many ways can he make his s
pashok25 [27]

Answer:

15,120 for the first question. 1,680 if one of the books is a must

Step-by-step explanation:

When Ron chooses his first book, he has 9 options. After that, when he chooses his second book, he only has 8 choices because he already picked one of them. By his third choice, he only has 7 choices and so on.

We can make an equation to represent this,

9 x 8 x 7 x 6 x 5

Multiplying all of that out gets you 15,120.

The second problem is even easier. Since one of the books is already chosen for him, he starts off only having 8 options. Since he is only choosing four books this time, we are only multiplying four numbers.

8 x 7 x 6 x 5

Multiplying all of that out tells you there are 1,680 ways he can make his selection in the second scenario.

5 0
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