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Keith_Richards [23]
4 years ago
10

What is the following quotient? √96/√8

Mathematics
2 answers:
Kipish [7]4 years ago
7 0
Hope this helps. Might have a few extra steps.

inysia [295]4 years ago
4 0

Answer:

2\sqrt{3}

Step-by-step explanation:

We are asked to find the quotient of expression: \frac{\sqrt{96}}{\sqrt{8}}

Upon using the quotient rules for radicals we will get,  

\frac{\sqrt{96}}{\sqrt{8}} =\sqrt{\frac{96}{8}

Now let us cancel out GCF of 96 and 8.

\sqrt{\frac{96}{8}}=\sqrt{12}

Now let us factor out perfect square from \sqrt{12}

\sqrt{12}=\sqrt{4}\times\sqrt{3}

\sqrt{4}\times\sqrt{3}=2\sqrt{3}

Therefore, our radical expression simplifies to 2\sqrt{3}.

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Step-by-step explanation:

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mr_godi [17]
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3 years ago
Can someone help me I dead do t understand
valkas [14]
You should use a double number number line
3 0
3 years ago
The directex of Y=1/8x^2 is?
nexus9112 [7]
\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\
\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})} \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
y=\cfrac{1}{8}x^2\implies (y-0)=\cfrac{1}{8}(x-0)^2\implies 8(y-0)=(x-0)^2
\\\\\\
4(2)(y-0)=(x-0)^2\impliedby \textit{that means, p = 2}

so... if you notice, the vertex is at h,k and that'd be the origin, 0,0

so...since the directrix is "p" units from the vertex, so it'd be 2 units from 0,0

now, the parabola has an equation with a positive leading term's coefficient, namely the 1/8 is positive, thus, the parabola is opening upwards, and the directrix is "outside" the parabola, so is below the vertex

that puts the directrix 2 units below 0,0

y = -2
6 0
3 years ago
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