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2 years ago

Help on math question please ( ASAP )

Mathematics

1 answer:

Deffense [45]2 years ago

4 0

Using the formula of the cone and cylinder given in my book, I've managed to give you an answer which is 4189 or to be exact 4188.80 as i used the information given to solve this problem

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Let m represent the number of children playing soccer. Those children are separated into 4 equal teams. Write an expression for

gladu [14]

children playing soccer, m

number of teams = 4

number if kids per team, f(m) = m/4

6 0

2 years ago

Out of 100 employees at a company, 92 employees either work part time or work 5 days each week. There are 14 employees who work

Alexus [3.1K]

Answer: 0.02

Step-by-step explanation:

OpenStudy (judygreeneyes):

Hi - If you are working on this kind of problem, you probably know the formula for the probability of a union of two events. Let's call working part time Event A, and let's call working 5 days a week Event B. Let's look at the information we are given. We are told that 14 people work part time, so that is P(A) = 14/100 - 0.14 . We are told that 80 employees work 5 days a week, so P(B) = 80/100 = .80 . We are given the union (there are 92 employees who work either one or the other), which is the union, P(A U B) = 92/100 = .92 .. The question is asking for the probability of someone working both part time and fll time, which is the intersection of events A and B, or P(A and B). If you recall the formula for the probability of the union, it is

P(A U B) = P(A) +P(B) - P(A and B).

The problem has given us each of these pieces except the intersection, so we can solve for it,

If you plug in P(A U B) = 0.92 and P(A) = 0.14, and P(B) = 0.80, you can solve for P(A and B), which will give you the answer.

I hope this helps you.

Credit: https://questioncove.com/updates/5734d282e4b06d54e1496ac8

7 0

2 years ago

PLEASE HELP FAST! UNIT TEST and I NEED A GOOD GRADE.

Crank

Slope = -5

y-intercept = 5

y = -5x + 5

Hope this helps! ;)

3 0

3 years ago

Suppose a manufacturer finds that 95% of their production is normal but the final 5% has one or more flaws. Each flawed good has

RUDIKE [14]

Answer:

FLAW TYPE2 NO TYPE2 FLAW

TYPE1 0.015 0.025

NO TYPE1 FLAW 0.01 0.95

2) 0.04 and $0.04

3) 0.025 and $0.025

4) 0.015 and $0.015

5) 0.95 and $0.95

Step-by-step explanation:

Given that;

financial cost = $1

p(flaw) = 0.05

p(type 1 flaw / flaw) = 80% = 0.8

p(type 2 flaw / flaw) = 50% = 0.5

p( type 1 and 2 flaw/flaw) = 30% = 0.30

1) Bivariate Table

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw) = 0.05 × 0.5 = 0.025

p( type 1 and 2 flaw) = p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

p( only 1 flow) = 0.04 - 0.015 = 0.025

p( only 2 flow) = 0.025 - 0.015 = 0.01

THEREFORE the Bivariate Table;

FLAW TYPE2 NO TYPE2 FLAW

TYPE1 0.015 0.025

NO TYPE1 FLAW 0.01 0.95

2) probability and expectations of type 1 flaw?

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

Expected financial cost to the firm per good = $1 × 0.04 = $0.04

3) probability and expectation of Type 2 flaw

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw) = 0.05 × 0.5 = 0.025

Expected financial cost to the firm per good = $1 × 0.025 = $0.025

4) probability and expectations of Type 1 and 2 flaws

p( type 1 and 2 flaw) = p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

Expected financial cost to the firm per good = $1 * 0.015 = $0.015

5) probability and expectations of no flaws?

Probability of no flaw = P(No flaw) =95% = 0.95

Expected financial cost saved the firm per good due to no flaw

= $1 × 0.95 = $0.95

5 0

3 years ago

the lenght of the longer leg of a right triangle is 9 ft longer than the lenght of the shorter leg x. The hypotenuse is 9 ft sho

trasher [3.6K]

Answer:

see below

Step-by-step explanation: 5 23 8 03

the lenght of the longer leg of a right triangle is 9 ft longer than the lenght of the shorter leg x. The hypotenuse is 9 ft shorter than twice the lenght of the shorter leg.

shorter leg = x

longer leg = x + 9

hypotenuse = 2x - 9

Pythagorean theorem = a² + b² = c²

shorter-leg² + longer-leg² = hypotenuse²

x² + (x+9)² = (2x - 9)² solve for x

x² + (x+9) (x+9) = (2x - 9)(2x - 9)

x² + (x²+18x+81) = (4x² - 36x + 81)

(2x²+18x+81) = (4x² - 36x + 81)

0 = 2x² -54x

0 = x(2x - 54)

0 = x and 0 = 2x -54

54 = 2x

27 = x

shorter leg = 27

longer leg = 36

hypotenuse = 45

divided all the values by 9 and you get a 3, 4, 5 right triangle, so the answer checks correct

6 0

2 years ago