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stepladder [879]

3 years ago

14

Sue uses the expression (8 x 3,000) + (8 x 200) + (8 x 9) to help solve a multiplication problem. What is Sue's multiplication p

roblem?

1 answer:

aniked [119]3 years ago

5 0

25,672 if you take it step by step you will get it

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Please Help, ASAP!

Sergio [31]

Answer:

Step-by-step explanation:

A WOMEN WOULD OVER HER LIFE THE TFR SO IF YOU RELATE THAT TO GOATS THE MALE BRITISH AND THE FEMALE BIRTH WOULD BE DEFERRED SO THE PROBABILITY WOULD BE WORSE.

6 0

3 years ago

What number is 80% of 660?

ddd [48]

Answer:

528

Step-by-step explanation:

(80:100)*660 =

(80*660):100 =

52800:100 = 528

Now we have: 80 percent of 660 = 528

7 0

3 years ago

Jill is factoring the expression 13XY -52y. Her work is shown below

Sunny_sXe [5.5K]

Answer:13y(x-4)

Step-by-step explanation:

13xy-52y =13y(x-4)

3 0

3 years ago

NEED ANSWER ASAP PLEASE HELP

Artyom0805 [142]

Step-by-step explanation:

the answer is C I'm 100% sure of it

3 0

3 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

8 0

3 years ago