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Lana71 [14]
4 years ago
6

Twins can be identical boys, identical girls, non-identical boys, non-identical girls or one boy and one girl. What are the poss

ible combinations with triplets?
Mathematics
1 answer:
Vika [28.1K]4 years ago
7 0

Answer:

See explanation

Step-by-step explanation:

Twins can be identical boys, identical girls, non-identical boys, non-identical girls or one boy and one girl.

For the triplets, first list all possibilities with children sexes:

3 boys

3 girls

2 boys and 1 girl

2 girls and 1 boy.

Hence, all possible combinations are:

3 identical boys

2 identical boys and 1 non-identical boy

3 non-identical boys

3 identical girls

2 identical girls and 1 non-identical girl

3 non-identical girl

2 identical boys and girl

2 non-identical boys and girl

2 identical girls and boy

2 non-identical girls and boy

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Contact [7]

Answer:

I cant read the handwriting sorry

Step-by-step explanation:

6 0
3 years ago
The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are
almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = <u><em>the number that are not correctly calibrated.</em></u>

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_3

So, the required probability = \frac{^{6}C_3}{^{8}C_3}  

                                              = \frac{20}{56}  = <u>0.35</u>

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_2

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_1

So, the required probability = \frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}  

                                                = \frac{30}{56}  = <u>0.54</u>

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = ^{8}C_3

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = ^{6}C_1

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = ^{2}C_2

So, the required probability = \frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}  

                                                = \frac{6}{56}  = <u>0.11</u>

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0
3 years ago
Find The Number of Combinations<br> 9C3
tiny-mole [99]

Answer:

Step-by-step explanation:

9C3=\frac{9*8*7}{3*2*1} =84

4 0
3 years ago
How many 1/6 centimeters of yarn are there in 3/4 centimeters of yarn?​
aliya0001 [1]

Answer:

Its 639 if that dosent help contact me ill help guadianeany time.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Lucas is making accessories for the soccer team. He uses 883.68 inches of fabric on headbands for 46 players and 2 coaches. He a
zimovet [89]

The total fabric used for headband and wristband of a player was: 27.84 inches

Step-by-step explanation:

The question will be solved step by step.

So,

Total ribbon used for headbands = 883.68 inches

Total number of people for whom headbands were made = 46 players + 2 coaches = 48 inches

so the headband for one person will use fabric:\frac{883.68}{48}\\= 18.41\ inches

Then

Total fabric used for wristbands = 433.78 inches

Total players = 46

Fabri\ for\ one\ player's\ wristband = \frac{433.78}{46}\\=9.43\ inches

Total fabric for one player = 18.41 + 9.43 = 27.84 inches

Hence,

The total fabric used for headband and wristband of a player was: 27.84 inches

Keywords: Fractions, decimals

Learn more about fractions at:

  • brainly.com/question/9527422
  • brainly.com/question/9381523

#LearnwithBrainly

6 0
3 years ago
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