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3 years ago

Use a related equation that has the variable on one side. Then simplify the other side. T/3 = 15. (A t = 15 ÷ 3; t = 5.)

Mathematics

1 answer:

gregori [183]3 years ago

6 0

It’s D bc Dt= 15x3 and it’s not that hard to solve

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How can you determine if two triangles are congruent when you are given the coordinates of the vertices ?

ivolga24 [154]

I would plot the points and then see from there

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3 years ago

Read 2 more answers

87 oz to lb to oz pls help still new and im stupid

Gekata [30.6K]

Answer:

5.4375 Pounds (lb)

Step-by-step explanation:

By using the calculator, and dont call your self stupid we all need help sometimes

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3 years ago

Find the perimeter RST. Round answer to the nearest tenth<br> Show all the work

kow [346]

Answer:

35.1 units

Step-by-step explanation:

Imagine a right-angled triangle with RS as hypotenuse. The base would be 3 units and the height would be 6 units. By Pythagorus:

RS²=3²+6²

RS= $\sqrt{45}$ ≈6.7 units

Imagine a right-angled triangle with RT as hypotenuse. The base would be 9 units and the height would be 12 units. By Pythagorus:

RT²=9²+12²

RT= $\sqrt{225}$ = 15 units

Imagine a right-angled triangle with TS as hypotenuse. The base would be 12 units and the height would be 6 units. By Pythagorus:

TS²=12²+6²

TS= $\sqrt{180}$ ≈13.4 units

Perimeter=RS+RT+TS

=6.7+15+13.4

=35.1 units

6 0

3 years ago

John wants to make cookies. To make cookies, he need 2 over 3 of a cup of flour per batch of cookies. If John has 4 cups of flou

Mnenie [13.5K]

$\dfrac{2}{3} \text { cups = } 1 \text { batch}$

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Find 1 cup :
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$1 \text { cup = } 1 \div \dfrac{2}{3} \text { batch}$

$1 \text { cup = } 1 \times \dfrac{3}{2} \text { batch}$

$1 \text { cup = } \dfrac{3}{2} \text { batch}$

----------------------------------------------
Find 4 cups :
----------------------------------------------
$4 \text { cups = } \dfrac{3}{2} \times 4 \text { batch}$

$4 \text { cups = } \6 \text { batches}$

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Answer: John can make 6 batches with 4 cups of flour.
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6 0

3 years ago

a cubic box has a side length of 2 feet. How many of these boxes could fit inside a larger cubic box whose base has a perimeter

kap26 [50]

So if a cubic box has a side length of 2 ft in order to find the volume we need to cube it or multiply the length times 3 times. so it would be 2x2x2=8. that is the volume of the fiest cube. in order to find the volume of the larger cube first you need to know the length of one of the sides. the base has 4 sides to it that are all equal so you divide 24 by 4 and get 6. then to find the volume you multiply 6 three times since it is also a cubic cube so it would be 6x6x6=216. now you know the volume of each cube so you divide 216 by 8 to find how many times the volume of the small cube would go into the volume of the larger cube and get 27 times.

6 0

3 years ago