He has 11 quarters, 9 dimes, and 55 nickels.
11x.25=2.75
9x.1=.9
55x.05=2.75
2.75+2.75+.9=6.4
3 / 29 = x / 116
29 x = 116 . 3
29 x = 348
x = 348 / 29
x = 12
hope this helps!
Answer:
The answer to your question is x = -2, y = 5 and z = 7
Step-by-step explanation:
Data
first number = x
second number = y
third number = z
Process
1.- Write equations to solve this problem
x + y + z = 10 Equation l
2y - x = 12 Equation ll
x - y + 2z = 7 Equation lll
2.- Solve equation ll for x
x = 2y - 12
3.- Substitute the previous equation in equation l and lll
(2y - 12) + y + z = 10 (2y - 12) - y + 2z = 7
2y - 12 + y + z = 10 2y - 12 - y + 2z = 7
3y + z = 10 + 12 y + 2z = 19
3y + z = 22
4.- Solve for y and z
-2(3y + z = 22)
y + 2z = 19
-6y - 2z = -44
y + 2z = 19
-5y + 0 = -25
y = -25/-5
y = 5
-Find z
5 + 2z = 19
2z = 19 - 5
2z = 14
z = 14/2
z = 7
5.- Find x
x + 5 + 7 = 10
x = 10 - 5 - 7
x = -2
Question 1:
For this case we have an equation of the form:
Where,
- <em>k: inverse variation constant.
</em>
Then, substituting values we have:
From here, we clear the value of k.
We have then:
Answer:
the constant of inverse variation is:
Question 2:
For this case we have:
Where,
- <em>k: constant of variation.
</em>
Then, substituting the value of the constant we have:
We now substitute the value of x:
Answer:
the value of y when x = 4 is:
Answer:
x=-44
Step-by-step explanation:
3/4(1/4x+8)-(1/2x+2)=3/8(4-x)-1/4
3/16x+24/4-1/2x-2=12/8-3/8x-1/4
3/16x+6-1/2x-2=3/2-3/8x-1/4
3/16x-1/2x+4=3/2-3/8x-1/4
-5/16x+4=-3/8x+5/4
Add 3/8x to both sides
-5/16x+4+3/8x=-3/8x+5/4+3/8x
1/16x+4=5/4
Subtract 4 from both sides
1/16x+4-4=5/4-4
1/16x=-11/4
Multiply both sides by 16
1/16x(16)=-11/4(16)
x=-44