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IceJOKER [234]
3 years ago
6

Given the quadratic function

Mathematics
1 answer:
Temka [501]3 years ago
3 0

Answer:

See below.

Step-by-step explanation:

A.  F(x)=3x^2 - 24x + 49


f(x) = 3(x^2 - 8x) + 49

f(x) = 3 [(x - 4)^2 - 16]  + 49

f(x) = 3(x - 4)^2 - 48 + 49

f(x) =  3(x - 4)^2 + 1  <------- Vertex form. (answer).

B.


The vertex is at (4, 1). (answer).

C.

The y-intercept occurs when x = 0:

y = 3(0- 4)^2 + 1

= 3*16 + 1

= 49

The y-intercept is at (0, 49). (answer)

The x intercepts occur when y = 0:

3(x - 4)^2 + 1 = 0

3(x - 4)^2 = -1

(x - 4)^2 = -1/3

Since there is no real square root of a negative there are no x-intercepts.

(Answer)


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