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3 years ago

PLZ HELP

Mathematics

2 answers:

Alenkinab [10]3 years ago

6 0

well the absolute means positive so it would be a positive 1.6

stepladder [879]3 years ago

4 0

Answer:

The absolute value of Point B labelled on the number line is 1.6.

Step-by-step explanation:

In a number line

Coordinate of point A = -2.2

Coordinate of point B = -1.6

Coordinate of point C = 1.2

We need to find the absolute value of Point B labelled on the number line.

Absolute value : Absolute value of a real number is the non-negative value of that number. Let x be a real number, then

$|x|=|-x|=x$

The absolute value of Point B is

$|-1.6|=1.6$

Therefore the absolute value of Point B labelled on the number line is 1.6.

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What do u notice to this picture?

trasher [3.6K]

Answer:

The picture has a pattern. The pattern in this picture is that each time 4 corners are added. You can also look at this as it adds 4 each time or as the equation. Y=5+4x. Y being The amount of cubes in the equation

3 0

3 years ago

What value or values of x satisfy 2x + 5.31 = 4.2?

Softa [21]

Answer: x can equal -3.2 or -7.4.

Step-by-step explanation:

The correct expression is:

2|x+5.3|=4.2

So, we have an absolute value equation, where it can be positive or negative:

Positive

2 (x+5.3)=4.2

2x+10.6 =4.2

2x=4.2-10.6

2x = -6.4

x= -6.4/2

x = -3.2

Negative

2[-(x+5.3)]=4.2

-2x-10.6 =4.2

-2x= 4.2+10.6

-2x= 14.8

x= 14.8/-2

x= -7.4

x can equal -3.2 or -7.4.

Feel free to ask for more if needed or if you did not understand something.

3 0

3 years ago

HELP PLEASE I'LL GIVE 30 POINTS!!!

jasenka [17]

Answer:

x = 45

Step-by-step explanation:

Straight line has 180 degrees; so if you add all the angles up:

2x + x + x = 180

4x = 180

x = 45 degrees

6 0

3 years ago

Read 2 more answers

Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex

siniylev [52]

Answer:

$\large \boxed{\sf \ \ \ p=-11 \ \ \ }$

Step-by-step explanation:

Hello,

$\alpha \text{ and } \beta \text{ are the roots of the following equation}$

$2x^2+6x-7=p$

It means that

$2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\$

And we know that

$\alpha= 2\cdot \beta$

So we got two equations

$2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1$