Answer:
(2pi)/5
Step-by-step explanation:
The cosine function cos(x) has a period of 2*pi.
If we change the argument of the cosine, the new argument will have a period of 2*pi. If the new argument is 5x, we have that the period will be:
5x = 2*pi
x = 2*pi/5
The period of this function will be (2pi)/5, because for every (2pi)/5 change in the value of x, the function will have the same value. The value of 5 multiplying the cosine does not interfere in the period.
Step-by-step explanation:
Answer:
V = 5000 + 275*T for simple annual interest
or: A = 5000 * (1.055)^T for an annual compound interest
Step-by-step explanation:
I assume this is a simple interest rate. If not I will give the one for compound interest.
V = 5000 + 5000* 0.055 * T (Value of account after T years)
V = 5000 + 275*T for simple annual interest
or: A = 5000 * (1.055)^T for an annual compound interest
<h2>There is no 4 odd digits that will add up to 19.</h2>
Answer:
The quotient is 3x - 11 + 60/(x + 5) ⇒ 2nd answer
Step-by-step explanation:
* We will use the long division to solve the problem
- The dividend is 3x² + 4x + 5
- The divisor is x + 5
- The quotient is the answer of the division
- If the divisor not a factor of a dividend, the quotient has
a remainder
* Lets solve the problem
- At first divide the first term in the dividend by the first term in
the divisor
∵ 3x² ÷ x = 3x
- Multiply the divisor by 3x
∴ 3x (x + 5) = 3x² + 15x
-Subtract this expression from the dividend
∴ 3x² + 4x + 5 - (3x² + 15x) = 3x² + 4x + 5 - 3x² - 15x = -11x + 5
- Divide the first term -11x in the new dividend by the first
term x in the divisor
∴ -11x ÷ x = -11
- Multiply the divisor by -11
∴ -11(x + 5) = -11x - 55
-Subtract this expression from the new dividend
∴ -11x + 5 - (-11x - 55) = -11x + 5 + 11x + 55 = 60
∴ The quotient is 3x - 11 with remainder = 60
* The quotient is 3x - 11 + 60/(x + 5)
