→ 6x² - 2x - 20
→ 6x² + 10x - 12x - 20
→ x(6x + 10 ) - 2 (6x + 10)
→ (6x + 10) (x - 2) .
for
6x - 10 = 0
6x = 10
for x - 2
x = 2
Answer:
Option A.
Step-by-step explanation:
The given equation is
Step 1: Multiply both sides by (x-4).
Step 2: Multiply both sides by 7.
Step 3: Using distributive property.
Step 4: Isolate all terms on one side.
Step 5: Find factors by splitting the middle term.
Step 6: Using zero product property, we get
It means student solved the equation correctly.
Therefore, the correct option is A.
The formula for arc length is:
s= r∅
Given that ∅= 7π/4
and r= 5
Therefore, arc length s= 7π/4 *5 = 35π/4
Given that R(ABCDE) is in Boyce-Codd normal form.
And AB is the only key for R.
Definition
A relational nontrivial Schema R is in BCNF if FD (X-A) holds in R, Super key of R. whenever then X is
a
Given that AB is the only key for R.
ABC E (Yes).
check if ABC is a Super key. AB is a key, ABC is A B C E is in BONE a super key.
2) ACE B
(NO). no Check if ACE As there is ACE is not a Super key? AB in Super key. ACE.
ACE B
is
Boyce-Codd Normal Form not in BENE (NO)
3) ACDE → B (NO)
check if is a super key. ACDE
As ACDE there is not any AB Tn ACDE. a super key.
ACDEB is not in BCNF.
4) BS → C → (NO)
As there is no AB in BC ~. B(→ not in BCNF
BC is not a super key.
5) ABDE (Yes).
Since AB is a key.
ABO TS a super key.
.. ABDE → E is in BCNF
Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AB is the only key for R, identify each of these FDs from the following list. Answer Yes or No and explain your answer to receive points.
1. ABC E
2. ACE B
3. ACDE B
4. BC C
5. ABD E
Learn more about Boyce-Codd Normal Form at
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