Step-by-step explanation:
i assume this is the question you asked me to look at.
Well, angle 116° and y are supplementary angles
therefore,116°+y=180°
y=180°-116°=64°
Now to find x
x+y+125+72=360°
x+64+125+72=360
x+261=360
x=360-261=99°
The transformed function is G(x) = -4x² after applying the transformation stretched vertically and flipped over the x-axis option (C) G(x) = -4x² is correct.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
The options are missing.
The options are:
A. G(x) = 4x²
B. G(x) = -(1/4)x²
C. G(x) = -4x²
D. G(x) = (1/4)x²
We have an equation of a function F(x)
F(x) = x²
The transformation F(x) can be stretched vertically and flipped over the x-axis to produce the graph of G(x)
To stretch vertically if the function is multiplied by a constant value
f(x) = ax²
To flip over the x-axis if multiply by negative value.
g(x) = -ax²
From the options
G(x) = -4x²
Thus, the transformed function is G(x) = -4x² after applying the transformation stretched vertically and flipped over the x-axis option (C) G(x) = -4x² is correct.
Learn more about the function here:
brainly.com/question/5245372
#SPJ1
If a single board measures 1/12 of a meter then it would take 12 boards to make a meter. Since, the stack is 2 meters high. You would multiply 12 and 2 to get 24. There is 24 boards in the stack.
I believe <span>angle 1 is 115°
</span>
Answer: z=0
Step-by-step explanation:
W=zr-2zt^3
Move all terms containing z to the left, all other terms to the right.
dd '-1rz' to each side of the equation.
-1rz+z=rz+-1rz+-2t^3z
Combine like terms: rz + -1rz = 0
-1rz+z=0+(-2t^3z)
-1rz+z=-2t^3z
Add 2t^3z to each side
-1rz+2t^3z+z=-2t^3z+2t^3z
Combine the like terms 2t^3z+2t^3z=0
-1rz+2t^3z+z=0
Factor out the Greatest Common Factor (GCF), 'z'.
z(-1r+2t^3+1)=0
Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)
- Cutiepatutie ☺❀❤