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3 years ago

Find the perimeter and area

Mathematics

2 answers:

Aleksandr [31]3 years ago

7 0

Answer:

P = 27.9

A = 27.25

Step-by-step explanation:

First we find the base using pythagorean theorem

c² = a² + b²

12² = 5² + b²

144 = 25 + b²

b² = 144 - 25

b² = 119

b = √ 119

b = 10.9

Perimeter = a + b + c

5 + 10.9 + 12 = 27.9

Area = 1/2 × b × h

A = 1/2 × 10.9 × 5

A = 54.5/2

A = 27.25

Therefore P = 27.9

A = 27.25

jeka943 years ago

3 0

Answer:

Area: 30 Perimeter: 22

Step-by-step explanation:

To find the area of the triangle you need to multiply the base and the length, which is directly perpendicular to the base. After multiplying, you will divide the product by 2 to get your answer, this is because a triangle is half a rectangle.

For the perimeter, I assumed that the empty side was a 5, please correct me if I am wrong. But to find the perimeter you need to add all the sides together, so I got 22.

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Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco

kari74 [83]

Answer:

C. $\frac{1}{18}$

Step-by-step explanation:

Given: Six cards numbered from $1$ to $6$ are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is $8$ , what is the probability that one of the two cards drawn is numbered $5$ .

Solution:

Sample space for sum of cards when two cards are drawn at random is $\{(1,1),(1,2),(1,3)......(6,6)\}$

total number of possible cases $=36$

Sample space when sum of cards is $8$ is $\{(3,5),(5,3),(6,2),(2,6),(4,4)\}$

Total number of possible cases $=5$

Sample space when one of the cards is $5$ is $\{(5,3),(3,5)\}$

Total number of possible cases $=2$

Let A be the event that sum of cards is $8$

$p(\text{A})$ $=\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}$

$p(\text{A})=\frac{5}{36}$

Let B be the event when one of the two cards is $5$

probability than one of two cards is $5$ when sum of cards is $8$

$p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}$

$p(\frac{\text{B}}{\text{A}})=\frac{2}{5}$

Now,

probability that sum of cards $8$ is and one of cards is $5$

$p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})$

$p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}$

$p(\text{A and B})=\frac{1}{18}$

if sum of cards is $8$ then probability that one of the cards is $8$ is $\frac{1}{18}$ , option C is correct.

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3 years ago

Rich is driving from Philadelphia to Pittsburgh at 70 mph and Michelle is driving from Pittsburgh to Philadelphia at 65 mph. If

Sliva [168]

Let:
Philadelphia be point a
Pittsburgh be point b
Distance traveled by Michelle be x
Distance traveled by Rich be 305 x

The general formula is:
distance = velocity (time)

substituting the values:
michelle: X = 65(t)
rich: 305 - X = 70 t

substituting both equations gives:
X = 146.562 miles

t = 2.26 hours or 2 hours and 15 mins

4 0

3 years ago

Help Me Solve This

olasank [31]

Let us assume the number of cd's you can buy = x
Cost of an used CD = $4.25
Total amount of money that you have = $1500
Then
<span>x ≤ 15 − 4.25
</span>x ≤ 10.75

I hope the procedure is clear enough for you to understand. I also hope that this is the answer that you were looking for and the answer has actually come to your desired help.

3 0

3 years ago

X + 7y = "70" 3x − 6y = −33 step by step

Aneli [31]

Answer:

x=7

y=9

Step-by-step explanation:

x+7y=70 ...(1)

3x-6y=-33

divide by 3

x-2y=-11 ...(2)

(1)-(2) gives

x+7y-x+2y=70+11

9y=81

y=9

x-2*9=-11

or x=-11+18=7

3 0

3 years ago

What's the value of x?

Alekssandra [29.7K]

Step-by-step explanation:

90 - 60 = 30

30 - 18 = 12

X=12

7 0

3 years ago