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ElenaW [278]
3 years ago
8

X^2 + 18x + c = 25 +c

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0
Rearrange to: x^2 + 18x - 25 = 0
Then factorise (I like to do it by completing the square):
(x + 9)^2 -81 -25 = 0
(x + 9)^2 = 106
x + 9 = sqrt(106)
The sol'ns are:
x = -9 + and - sqrt(106)
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What is the logarithmic form of the equation e3x ≈ 3247?
lesya [120]
E^(3x) = 3247

3x = log 3247

x = [log 3247]/3
8 0
3 years ago
A trangle has a 30 angle and a 55angle .what is the other angle ?how do you know?​
algol [13]

Answer:

95°

Step-by-step explanation:

  • <em>Sum of 3 angles of a triangle equals to 180°</em>

<u>Here we have angles of 30° and 55°, so the remaining angle is:</u>

  • 180° -(30° + 55°) = 95°
5 0
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How do I solve this?
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Pls solve this<br> we need to find radius of this shape
Strike441 [17]
(not sure )
my method
let projection of b onto line dq be M
BM is 2r
then let the remaining angle ( right) be K
in triangle BMK ,
MK = 29-5-r
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5 0
3 years ago
For the graph, what is a reasonable constraint so that the function is at least 300?
blsea [12.9K]

Answer:

C) 0 ≤ x ≤ 25

Step-by-step explanation:

We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300

A)x ≥ 0

Refer the graph

At x = 0

f(x)=300

On increasing the value of x , f(x) increases but at x = 12 it starts decreasing

So, x ≥ 0 can also have f(x)<300

So, Option A is wrong

B)−5 ≤ x ≤ 30

At x = -5

f(x) = 100

So, Option B is wrong since we require f(x) is greater or equal to 300

c)0 ≤ x ≤ 25

At x = 0

f(x)=300

At x = 12 , it starts decreasing

At x = 25

f(x)=300

So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25

D)All real numbers

At x = 30

f(x)=0

But we require f(x) greater or equal to 300

Hence Option C is true

8 0
3 years ago
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