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2 years ago

How many moles of a gas are in a 2.2 liter balloon at 1.3 atm and 85oC?

Mathematics

2 answers:

Solnce55 [7]2 years ago

7 0

Answer: n= 0.059 moles of gas

Step-by-step explanation:

vampirchik [111]2 years ago

4 0

Answer:

0.059 moles of gas

Step-by-step explanation:

P=600/ 760

P=0.79atm

then

n = PV/RT

n= 0.79 X 2.2 / 0.08206 X (85+273)

n= 0.059 moles of gas

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A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h

Tanya [424]

Answer:

192 cm^3/min

Step-by-step explanation:

Differentiating the volume expression, we get ...

dV/dt = 2xh(dx/dt) +x^2(dh/dt)

We are given that ...

x = 4 cm, dx/dt = 2 cm/min, h = 15 cm, dh/dt = -3 cm/min

Putting these values into the formula for volume rate of change, we get ...

dV/dt = 2(4 cm)(15 cm)(2 cm/min) +(4 cm)^2(-3 cm/min)

= 240 cm^3/min -48 cm^3/min

dV/dt = 192 cm^3/min

8 0

2 years ago

What is the value of y when -5 = = y - 7? 9 a. -7 b.-11 C. -38 d. -52

weqwewe [10]

Answer:

Step-by-step explanation:

You have to cancel the -7 so you would add +7 to each side.

-7+7=0, -5+7= 2

y=2

Although this isn't an answer choice. Did you mistype something?

8 0

3 years ago

Which expression represents the sum of (2x-5y and (x+y) ?

gayaneshka [121]

I have no clue you have to do something like x2-x1 over y1-y2 and you get yoyu answer from that.

8 0

3 years ago

Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?

likoan [24]

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=15,\:\quad a_n=2$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}$

$-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3$

$\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5$

$=\left(x+3\right)\left(2x^2-11x+5\right)$

$Factor: 2x^2-11x+5$

$2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)$

$=x\left(2x-1\right)-5\left(2x-1\right)$

$2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)$

$\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:}$

thus zeros of f(x) is

$x=-3,\:x=5,\:x=\frac{1}{2}$

5 0

2 years ago

Read 2 more answers

(CO 4) In a sample of 8 high school students, they spent an average of 24.8 hours each week doing sports with a sample standard

AveGali [126]

Answer:

(22.12, 27.48)

Step-by-step explanation:

Given : Significance level : $\alpha: 1-0.95=0.05$

Sample size : n= 8 , which is a small sample (n<30), so we use t-test.

Critical values using t-distribution: $t_{n-1,\alpha/2}=t_{7,0.025}=2.365$

Sample mean : $\overline{x}=24.8\text{ hours}$

Standard deviation : $\sigma=3.2\text{ hours}$

The confidence interval for population means is given by :-

$\overline{x}\pm t_{n-1,\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

i.e. $24.8\pm(2.365)\dfrac{3.2}{\sqrt{8}}$

$24.8\pm2.67569206001\\\\\approx24.8\pm2.68\\\\=(24.8-2.68, 24.8+2.68)=(22.12, 27.48)$

Hence, the 95% confidence interval, assuming the times are normally distributed.= (22.12, 27.48)

6 0

2 years ago