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Charra [1.4K]
3 years ago
5

Find the Factor of 6x 2 - 17x + 5.

Mathematics
2 answers:
nydimaria [60]3 years ago
5 0
6x² -17x +5 = (6x² - 2x) - (15x + 5)    (factoring by grouping)

2x (3x -1) - 5(3x - 1)   


(2x -5) (3x - 1) is your final answer

hope this helps
n200080 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

6x^2-17x+5

This can be written as

6x^2-15x-2x+5

Because -15-2=-17 and also (-15)(-2)=30

so now we have two pairs

(6x^2-15x)+(-2x+5)

Take out GCF from each pair

3x(2x-5)-1(2x-5)

since (2x-5) is now the common factor so final factored form

(3x-1)(2x-5)

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4 years ago
In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8;
Fiesta28 [93]

We have to find the expansion of (3a+4b)^{8}

We will use binomial expansion to expand the given expression, which states that the expression (a+b)^{n} is expanded as :

(a+b)^{n}=^{n}C_{0}a^{n}+^{n}C_{1}a^{n-1}b+^{n}C_{2}a^{n-2}b^{2}+........^{n}C_{n}b^{n}

Now expanding (3a+4b)^{8} we get,

(3a+4b)^{8}=^{8}C_{0}(3a)^{8}+^{8}C_{1}(3a)^{7}(4b)+^{8}C_{2}(3a)^{6}(4b)^{2}+^{8}C_{3}(3a)^{5}(4b)^{3}+^{8}C_{4}(3a)^{4}(4b)^{4}+^{8}C_{5}(3a)^{3}(4b)^{5}+^{8}C_{6}(3a)^{2}(4b)^{6}+^{8}C_{7}(3a)(4b)^{7}+^{8}C_{8}(4b)^{8}

(3a+4b)^{8}=^{8}C_{0}(3)^{8}a^{8}+^{8}C_{1}(3)^{7}(4)(a^{7}b)+^{8}C_{2}(3)^{6}(4)^{2}(a^{6}b^{2})+^{8}C_{3}(3)^{5}(4)^{3}(a^{5}b^{3})+^{8}C_{4}(3)^{4}(4)^{4}(a^{4}b^{4})+^{8}C_{5}(3)^{3}(4)^{5}(a^{3}b^{5})+^{8}C_{6}(3)^{2}(4)^{6}(a^{2}b^{6})+^{8}C_{7}(3)(4)^{7}(ab^{7})+^{8}C_{8}(4)^{8}(b^{8})

So, the variables are a^{5}b^{3} , b^{8} , a^{4}b^{4} , a^{8}  , [tex] ab^{7}

5 0
3 years ago
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7 0
3 years ago
You buy 10 pounds of bird seed at store A for $11.50.Your friend buys 15 pounds of bird seed at Store B for $19.50.How much less
Dmitry [639]

Answer:

$3

Step-by-step explanation:

You buy 10 pounds of bird seed at store A for $11.50 which means every pound is $1.15.

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So, 26 - 23 = 3

3 0
2 years ago
Read 2 more answers
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