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ValentinkaMS [17]
3 years ago
8

s="latex-formula">
​
Mathematics
2 answers:
Art [367]3 years ago
8 0
The answer is -110.
This is because -55-55=-110.
You have to put -55-55 because the question is asking for you to multiply -55 twice, which is technically-55-55.
maks197457 [2]3 years ago
5 0
Answer:
(-55) • 2
-110
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Which of the following is independent variable?
satela [25.4K]

I think the answer is D. hours because its variation does not depend on another variable

6 0
3 years ago
I need help asappppppppppppp
svetoff [14.1K]

Answer: Choice [D] - "power of a power" ✅

Step-by-step explanation:

Hii, do you need to know which law you should use to simplify \sf\bigg(x^4\bigg)^9?

No problem!

The law we will use here is "power of a power".

What "power of powers" means is we raise a power to a power, which is exactly what we do here: We raise x^4 to the power of 9. To simplify our expression, we multiply the powers. (\boldsymbol{4\cdot9})

So the right answer is: Choice [D] - "Power of a power"

The simplified answer is \LARGE\boldsymbol{x^{4\cdot9}=x^{36}}

Voila! There's our answer, cheers!

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Hope that this helped! Best wishes.

\it Reach\;far.\;Aim\;high.\;Dream\;big.}

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7 0
1 year ago
Topic 9 Review
Lesechka [4]
Merry Christmas and a happy new year
3 0
3 years ago
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
2 years ago
Se desea constrir una barda utilizando block . las dimensiones de la barda son 25 m de largo y 2 m de altura . si se requieren 1
Andrew [12]

Answer:

I don't understand the language

Step-by-step explanation:

am not form Paris

3 0
2 years ago
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