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saw5 [17]
3 years ago
11

If i have 18 apples and i get 1328 more how many apples would i have

Mathematics
2 answers:
devlian [24]3 years ago
6 0

Darling, this problem is quite simply addition. You add 18 to 1328. 1328 + 18. we add the eights first. 8 + 8 equals 16. The 6 stays and we carry the one. 1 + 2 is 3. And then we add our carried 1 to make 4. So, the answer is 1346. I hope this helped!

max2010maxim [7]3 years ago
5 0
You add 1328+18 and you get your answer
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work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the​ conference is 0.10.

(c) The probability that Clarice attends the​ conference is 0.40.

(d) The probability that John stays​ home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

{5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event <em>E</em> is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of  Roberto and John is, <em>RJ</em>.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the​ conference as follows:

P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10

Thus, the probability that Roberto and John attend the​ conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the​ conference as follows:

P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40

Thus, the probability that Clarice attends the​ conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays​ home as follows:

P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60

Thus, the probability that John stays​ home is 0.60.

4 0
3 years ago
Which of the following coordinates exists on the line y = 3x + 1?
tankabanditka [31]

Answer:

D

Step-by-step explanation:

-2 = 3(-1) +1

-2 = -3 + 1

-2 = -2

8 0
3 years ago
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Ksenya-84 [330]

Answer:

You have 767.76 mL of soap.

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RoseWind [281]
Square root of 4 is 2
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3 years ago
Please answer i need help please i will give you brainlest please
Shkiper50 [21]

Answer:

14) 4x+10=8x-26 (corresponding angles are equal)

4x-8x=-26-10

-4x=-36

x= -36/-4= 9

x=9

15) perimeter of rectangle= 2(l+b)

2( l+ \frac{2l}{3}) = 40m

2l+ \frac{4l}{3} =40

Take LCM as 3

\frac{2l}{1} * \frac{3}{3} + \frac{4l}{3} =40

\frac{6l+4l}{3} = 40

\frac{10l}{3} = 40

10l=40*3

10l = 120

l= 120/10 =12 cm

l=12cm

b= 2/3 *12 = 8cm

16) 2:3:4

It can be written as 2x+3x+4x

sum of angles of a triangle =180 degree

so 2x+3x+4x=180

9x=180

x=180/9=20 degree

1st angle=2x=2*20= 40 degree

2nd angle= 3x=3*20 =60 degree

3rd angle= 4x=4*20= 80 degree

17) sum of interior angles of a pentagon is 540 degree

so, 125+88+128+60+x=540 degree

401 +x= 540 degree

x=540-401= 139 degree

<em>Hope this helps</em>

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6 0
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