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Paul [167]
3 years ago
9

Order each set of numbers from least to greatest 0.99 0.89 7/8

Mathematics
1 answer:
kifflom [539]3 years ago
3 0
7/8 = 0.875
1. 7/8
2. 0.89
3. 0.99 
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The mean survivial time after diagnosis for a certain disease is 15 years with a standard deviation of 5 years. Based on a parti
frutty [35]

Answer:

The time the patient expected to survive after diagnosis is 29 years.

Step-by-step explanation:

It is provided that the mean survival time after diagnosis for a certain disease is 15 years with a standard deviation of 5 years.

That is,

\mu=15\\\sigma=5

An individual's predicted survival time is <em>a</em> = 2.8 standard deviations beyond the mean.

Compute the time the patient expected to survive after diagnosis as follows:

X=\mu+a\sigma

    =15+(2.8\times 5)\\\\=15+14\\\\=29

Thus, the time the patient expected to survive after diagnosis is 29 years.

5 0
3 years ago
Which answer explains the correct way to move the decimal to find the product of 15.31 × 103?
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A. two places to the left
8 0
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Tyler ate x fruit snacks, and Han ate 3/4 less that. write an expression for the number of fruit snacks Han ate​
Alika [10]

x = ×-3/4

because you hace the variable x and you do not know the number of fruit snacks he ate and you need to have the same variables to properly find the answer.

3 0
3 years ago
Help! I will give brainliest!
alekssr [168]

Answer:

B 24

Step-by-step explanation:

3/5 is 54°

1/3 is 30°

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8 0
3 years ago
A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}

The information provided is:

<em>x</em> = number of students who responded as"yes" = 70

<em>n</em> = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

p=\frac{x}{n}

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

[1] 0.35

> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0
3 years ago
Read 2 more answers
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