3 years ago

The answer to this problem

Mathematics

1 answer:

Alexxandr [17]3 years ago

7 0

What problem? i need an example or picture... sorry

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The equation of a circle whose center is at ( 4,0 ) and radius is length 2 ( square root ) 3

Vesna [10]

The equation of a circle:
$(x-h)^2+(y-k)^2=r^2$
(h,k) - the coordinates of the center
r - the radius

The center is (4,0), the length of the radius is 2√3.
$(x-4)^2+(y-0)^2=(2\sqrt{3})^2 \\
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Solution:

2(6+7)= 3(5+2)

Step ; 1 { Solving first Term i.e LHS }

LHS : 2 ( 6 + 7)

☞ 2 ( 13)

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Now, RHS ; 3 ( 5 + 2)

☞ 3 ( 7)

☞ 21

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Therefore, 26≠ 21.

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3 years ago

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Soloha48 [4]

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Step-by-step explanation:

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