4 encuentros,creo Ó 2 encuentros.Pero yo creo que 4
That's the furthest it can be simplified.
The distances from D to the both sides(AB and AC) of the triangle are 4 ft.
<u><em>Explanation</em></u>
In the diagram below, ABC is a triangle in which ∠CAB = 60°
As, AD is the angle bisector of ∠CAB, that means ∠CAD = ∠DAB = 30°
The distance from D to side AC is DE and distance from D to side AB is DF. That means both ∠AED and ∠AFD are right angle.
Given that, the length of AD = 8 ft.
So, in right angle triangle AED.....
Also, in right angle triangle AFD....
So, the distances from D to the both sides(AB and AC) of the triangle are 4 ft.
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Answer:
04 or -3 because the it can get doubled