If x and y are two nonnegative numbers and the sum of twice the first ( x ) and three times the second ( y ) is 60, find x so th
at the product of the first and cube of the second is a maximum.
1 answer:
If we translate the word problems to mathematical equation,
2x + 3y = 60
The second equation is,
P = xy³
From the first equation, we get the value of y in terms of x.
y = (60 - 2x) / 3
Then, substitute the expression of y to the second equation,
P = x (60-2x) / 3
P = (60x - 2x²) / 3 = 20x - 2x²/3
We derive the equation and equate the derivative to zero.
dP/dx = 0 = 20 - 4x/3
The value of x from the equation is 15.
Hence, the value of x for the value of the second expression to be maximum is equal to 15.
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