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vazorg [7]
3 years ago
13

Please help me!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Reika [66]3 years ago
7 0
First, we can factor out a 2 from the equation:

2(x²-4x-12)=0

Divide by 2 to simplify

x²-4x-12=0

Now to factor, we must find what multiplies to -12, but adds to get -4. I can tell you know, the numbers are -6 and 2 (Through time you will learn to get faster with factoring)

Now we set it up as so:

(x-6)(x+2) = 0

Now to find the solutions, you must find how to get each set of parenthesis equal to 0.
x-6=0
x=6 is a solution

x+2=0
x=-2 is a solution as well.

So your answer is x=6 and -2 (Answer Choice C)

I Hope this Helps!
-Sinnamin

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What is the greatest integer a, such that a^2 + 3b is less than (2b)^2, assuming that b is 5? Please answer and have a nice day!
solniwko [45]
<h3>Answer: Largest value is a = 9</h3>

===================================================

Work Shown:

b = 5

(2b)^2 = (2*5)^2 = 100

So we want the expression a^2+3b to be less than (2b)^2 = 100

We need to solve a^2 + 3b < 100 which turns into

a^2 + 3b < 100

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after substituting in b = 5.

------------------

Let's isolate 'a'

a^2 + 15 < 100

a^2 < 100-15

a^2 < 85

a < sqrt(85)

a < 9.2195

'a' is an integer, so we round down to the nearest whole number to get a \le 9

So the greatest integer possible for 'a' is a = 9.

------------------

Check:

plug in a = 9 and b = 5

a^2 + 3b < 100

9^2 + 3(5) < 100

81 + 15 < 100

96 < 100 .... true statement

now try a = 10 and b = 5

a^2 + 3b < 100

10^2 + 3(5) < 100

100 + 15 < 100 ... you can probably already see the issue

115 < 100 ... this is false, so a = 10 doesn't work

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