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Katena32 [7]
3 years ago
6

Please help with question 2-6! no one wants to help me out

Mathematics
2 answers:
Zanzabum3 years ago
5 0

Answer:

OMGGGGG I remmeber this :,) But sadly I failed math so sorry :((

Step-by-step explanation:

NeTakaya3 years ago
4 0

Answer:

ooff I have a -12 in math rn

Step-by-step explanation: sorry muh guy/gal can't help ya

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A total of 635 tickets were sold for the school play. They were either adult tickets or student tickets. There were 65 fewer stu
goldfiish [28.3K]
You can make an equation for this (x is the number of student tickets)
x + (x + 65) = 635 \\ 2 x + 65 = 635 \\ 2x = 635 - 65 \\ 2x = 570
x =  \frac{570}{2}  = 285
the number of student tickets is 285

the number of adult tickets is 285+65=350



good luck
7 0
3 years ago
In a certain​ chemical, the ratio of zinc to copper is 3 to 11. A jar of the chemical contains 264 grams of copper. How many gra
natka813 [3]

Answer:

57

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Simplify:<br>2√3/16 - √75/16 + 2√27/16<br>a. 3/4√3<br>b. 1/2√3<br>c.5/4√3<br>d.0​
erastova [34]

Answer:

a.

Step-by-step explanation:

2√3/16 - √75/16 + 2√27/16

2/4√3 - 5/4√3 + 6/4√3

3/4√3

5 0
3 years ago
N 30 divided by (negative 6)?
Shtirlitz [24]
30/-6 equals 5. You’re welcome
8 0
3 years ago
In a circle a chord 10 inches long is parallel to a tangent and bisects the radius drawn to the point of tangency. How long is t
Lorico [155]
Check the picture below.

keeping in mind that the point of tangency for a radius line and a tangent is alway a right-angle, since the "red" chord is parallel to the "green" tangent line outside, then the chord is cutting the "green" radius there in two equal halves at a right-angle, as you see in the picture.

we know the chord is 10 units long, so 5 + 5, since is perpendicularity with the radius will also cut the chord in two equal halves.

anyhow, all that said, we end up with triangle you see on the right-hand-side, and then we can just use the pythagorean theorem.

\bf \textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;-------\\&#10;c=2a\\&#10;a=a\\&#10;b=5&#10;\end{cases}\implies (2a)^2=a^2+5^2

\bf (2^2a^2)=a^2+25\implies 4a^2=a^2+25\implies 3a^2=25&#10;\\\\\\&#10;a^2=\cfrac{25}{3}\implies a=\sqrt{\cfrac{25}{3}}\implies a=\cfrac{\sqrt{25}}{\sqrt{3}}\implies a=\cfrac{5}{\sqrt{3}}&#10;\\\\\\&#10;\textit{and then we can \underline{rationalize the denominator} }&#10;\\\\\\&#10;a=\cfrac{5}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies a=\cfrac{5\sqrt{3}}{\sqrt{3^2}}\implies a=\cfrac{5\sqrt{3}}{3}

7 0
3 years ago
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