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Dominik [7]
3 years ago
7

Patrick is replacing a door in his house. It has a height of 80 inches and its diagonal is 89 inches. What is the width of the d

oor?
The door is __________ inches wide.
Mathematics
1 answer:
Sedbober [7]3 years ago
6 0
72 I think I hope its right I had to write all over my paper lol
You might be interested in
Please answer asap thanks.
Hitman42 [59]

Answer:

94cm²

Step-by-step explanation:

S = 2(lw + lh + wh)

=2(20+15+12)

=40+30+24

=94cm²

Hope this helps! Can u give me brainliest, please:)

7 0
2 years ago
Read 2 more answers
A grandsons age in years is equal to his grandfather's age in years. The difference of the grandsons age in years and the grandf
garik1379 [7]

The age of the grandson is 7 years and the grandfather is 84 years if the grandson's age in months is equal to the age of grandpa in years and the difference in age is 77.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

Let's suppose the age of the grandsons is x years and

age of the grandfather's age is y years

Here some data are misprinted, so we are assuming the grandson's age in months is equal to the age of grandpa in years and the difference in age is 77.

Then according to the problem:

12x = y  (as in 1 year, there are 12 months)

y -x = 77 (as difference in age is 77)

After solving both equations, we get:

x = 7 years and y = 84 years

Thus, the age of the grandson is 7 years and the grandfather is 84 years if the grandson's age in months is equal to the age of grandpa in years and the difference in age is 77.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

4 0
2 years ago
Suppose a shoe factory produces both low-grade and high-grade shoes. The factory produces at least twice as many low-grade as hi
umka2103 [35]

Answer:

The factory should produce 166 pairs of high-grade shoes and 364 pairs of low-grade shoes for maximum profit

Step-by-step explanation:

The given parameters for the shoe production are;

The number of low grade shoes the factory produces ≥ 2 × The number of high-grade shoes produced by the factory

The maximum number of shoes the factory can produce = 500 pairs of shoes

The number of high-grade shoes the dealer calls for daily ≥ 100 pairs

The profit made per pair of high-grade shoed = Birr 2.00

The profit made per of low-grade shoes = Birr 1.00

Let 'H', represent the number of high grade shoes the factory produces and let 'L' represent he number of low-grade shoes the factory produces, we have;

L ≥ 2·H...(1)

L + H ≤ 500...(2)

H ≥ 100...(3)

Total profit, P = 2·H + L

From inequalities (1) and (2), we have;

3·H ≤ 500

H ≤ 500/3 ≈ 166

The maximum number of high-grade shoes that can be produced, H ≤ 166

Therefore, for maximum profit, the factory should produce the maximum number of high-grade shoe pairs, H = 166 pairs

The number of pairs of low grade shoes the factory should produce, L = 500 - 166 = 334 pairs

The maximum profit, P = 2 × 166 + 1 × 364 = 696

6 1
3 years ago
Read 2 more answers
Given s(x) = 2x - 3 and t(x) = 5x + 4. Find the formula and domain for v(x) = s (x) / t (x) and w(x) = t (x) / s (x)
Liula [17]
V(x) = (2x - 3)/(5x + 4)
The domain is all Real numbers except x = -4/5, because if x = -4/5 the denominator would be zero and you cannot divide by zero.
{x | x ∈ R, x ≠ -4/5}

w(x) = (5x + 4)/(2x - 3)
similarly, x ≠ 3/2
so, {x| x ∈ R, x ≠ 3/2}
8 0
4 years ago
Read 2 more answers
According to this diagram, what is cos 28°? 62° 17 8 28° 90° 15 O A. 17 15 O B. 8 17 O c. 15 17 O D. O E. 8 15 15 OF.​
VikaD [51]

Answer:

C. Cos(28) = \frac{15}{17}

Step-by-step explanation:

Recall: SOHCAHTOA

Thus,

Cos(\theta) = \frac{Adjacent}{Hypotenuse}

Reference angle = 28°

Adjacent = 15

Hypotenuse = 17

Plug in the values

Cos(28) = \frac{15}{17}

4 0
3 years ago
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