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3 years ago

If quadrilateral ABCD is congruent to quadrilateral EFGH, then what corresponding side is congruent to side EF? (5 points)

Mathematics

1 answer:

leonid [27]3 years ago

6 0

Answer:

Side AB

Step-by-step explanation:

Draw two congruent quadrilaterals.

Label the sides of one A,B,C,and D.

Label the sides of the other E,F,G,and H

Because the sides match up with the order in which they appear in if they are congruent, The first two letters(E and F) should be equivalent to the first two letters of the other shape(A and B).

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Which equation represents the line with slope 1/4 that passes through (-4, 8)?

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Step-by-step explanation:

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3 years ago

A box contains six red popsicles, two blue popsicles, and eight orange

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3 years ago

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The base of a triangle is nine centimeters longer than the perpendicular height. If the area of the triangle is 180 square centi

Rom4ik [11]

Answer:

Step-by-step explanation:

<u>Equations</u>

Let's call

b= base of the triangle

h=height of the triangle

The base is 9 cm longer than the height, thus:

b = h + 9

The area of the triangle is:

$\displaystyle A=\frac{bh}{2}$

$\displaystyle A=\frac{(h+9)h}{2}$

And its value is 180:

$\displaystyle \frac{(h+9)h}{2}=180$

Multiplying by 2:

$(h+9)h=360$

Operating:

$h^2+9h-360=0$

Factoring:

$(h-15)(h+24)=0$

The only valid positive solution is:

h = 15 cm

And b = h + 9 = 24

b = 24 cm

The base is 24 cm long.

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3 years ago

If Rodney traded €228.75 for $314.52, when did he make his exchange?

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3 years ago

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A triangle has a base of 3⅖ inches and an area of 5⅒ square inches. Find the height of the triangle. Show your reasoning

N76 [4]

Answer: 3 in.

Step-by-step explanation:

Given

The base of the triangle is $3\frac{2}{5}\ inches$

The area of the triangle is $5\frac{1}{10}\ inches^2$

Solve mixed fraction

Base is

$=3\dfrac{2}{5}\\\\=\dfrac{17}{5}\ in.$

Area is

$=5\dfrac{1}{10}\\\\=\dfrac{51}{10}\ in.^2$

The area of the triangle is given by

$\Rightarrow \text{Area A=}\dfrac{1}{2}\times \text{base}\times \text{height}$

Insert the values to get the height

$\Rightarrow \dfrac{51}{10}=\dfrac{1}{2}\times \dfrac{17}{5}\times \text{height}\\\\\Rightarrow \text{height}=3\ in.$

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3 years ago