Answer: B. 0.4772
Step-by-step explanation:
Given : The mean time : 
Standard deviation : 
Let X be the service time of a randomly selected customer.
Assuming a normal distribution, the value of z-score is given by :-

For x = 64

For x = 100

The p-value =

Hence, the probability that a randomly chosen customer experiences service done between 64 and 100 minutes = 0.4772
Answer:
53.3333.
Step-by-step explanation:
Since were asking to put 32 in the form of this ratio, we need to first turn the ratio into a fraction, in our case it is 5/3. Next we multiply 32 by 5/3 or to make it more simple multiply 32 by 5 to get 160, then divide 3 to get 53.3...
Hope this helps.
Answer:
-16394
Step-by-step explanation:
Pattern rule : Start at -2 and multiply it by -2.
-2 x -2 = 4
4 x -2 = -8
-8 x -2 = 16
16 x -2 = -32
- 32 x -2 = 64...so on
True, regarding the function is (–6, 10) f(–6) = 10