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erastovalidia [21]
2 years ago
11

Isaiah has $7.15 in Dimes and Nickels.He has a total of 91 coins.How many good each coin does he have?

Mathematics
1 answer:
lawyer [7]2 years ago
3 0
He have about 0 dime and 69 coins each
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One number is 2 more than 3 times another. Their sum is 22. Find the numbers. 8, 14 5, 17 2, 20 4, 18 10, 12
xxTIMURxx [149]

9514 1404 393

Answer:

  (b)  5, 17

Step-by-step explanation:

You can try the answer choices easily enough.

  2 +3×8 ≠ 14

  2 +3×5 = 17 . . . . this choice works (5, 17)

  2 +3×2 ≠ 20

  2 +3×4 ≠ 18

  2 +3×10 ≠ 12

__

Or, you can solve the equation:

  x + (2 +3x) = 22

  4x = 20 . . . . . . . . subtract 2

  x = 5 . . . . . . . . . . divide by 4

The numbers are 5 and (22 -5) = 17.

5 0
2 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
2 years ago
12.10 rounding to the nearest 10th
Sedaia [141]

Answer:

12

Step-by-step explanation:

Your answer is 12. I hope this helps!!!

6 0
2 years ago
HELP PLEASE NO LINKS OR FILES THEY WILL BE REPORTED
Mariana [72]

Answer:

One of the possible dimensions of the full trailer could be 5 by 12 by 3.

Step-by-step explanation:

Volume = weight times height times length = 12 times 5 times 3 = 180.

3 0
2 years ago
HELP I NEED HELP ASAP
masha68 [24]

Answer:

i think it's c but I'm rly not sure on this one...

3 0
2 years ago
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