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Murljashka [212]
3 years ago
13

-1/2 x -1/7 I do not understand how to do this

Mathematics
2 answers:
Firdavs [7]3 years ago
8 0

Answer:

sss

Step-by-step explanation:

Kobotan [32]3 years ago
6 0

Answer:

\dfrac{1}{14}

Step-by-step explanation:

1. You are multiplying two negative numbers. Negative times negative is positive, so the answer is positive.

2. To multiply two fractions, multiply together the numerators and multiply together the denominators.

-\dfrac{1}{2} \times -\dfrac{1}{7} =

= \dfrac{1 \times 1}{2 \times 7}

= \dfrac{1}{14}

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Is each line parallel, perpendicular, or neither parallel nor perpendicular to the line −x+4y=20?
PSYCHO15rus [73]
-x+4y=8: Parallel
4x+y=-1: Perpendicular
y=-1/4x+6: neither
y=-4x-3: Perpendicular
5 0
3 years ago
Read 2 more answers
Please solve and explain <br><br>4w(w-3)=24<br>​
nadya68 [22]

Step-by-step explanation:

4w (w - 3) = 24

4w^2 - 12w = 24

4w^2 - 12w - 24 = 0

use calculator, EQN if using Casio

the answer will be

w = _____ w = _____

5 0
3 years ago
If tan = 12/5 and cos = -5/13, then what is sin?
Over [174]

9514 1404 393

Answer:

  sin -12/13

Step-by-step explanation:

You can use the identity ...

  tan = sin/cos

to solve for sine:

  sin = cos·tan

  sin = (-5/13)(12/5) =

  sin -12/13

4 0
3 years ago
Yumi and Juan pick up litter along the highway at the same rate. Yumi picks up litter for 3 miles and takes two hours longer tha
oksano4ka [1.4K]
Juan's time = x
Yumi's time = x + 2
Yumi's distance = 3 miles
Juan's distance = 2 miles
Rate = distance/time
Juan's rate = 2/x
Yumi's rate = 3/(x + 2)
The rates are equal so:
2/x = 3/(x + 2)
2x + 4 = 3x
x = 4 hours
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3 0
3 years ago
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Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
3 years ago
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