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4 years ago

I need quick! 20 points!

1 answer:

7 0

Given is h(x) = 4x − 5 and t(x) = 2x + 4.

Part A: Finding (h + t)(x)
$(h + t)(x) = (4x - 5) + (2x + 4) \\ (h + t)(x) = 4x - 5 + 2x + 4 \\ (h + t)(x) = 4x + 2x - 5 + 4 \\ (h + t)(x) = 6x - 1$

Part B: Finding (h ⋅ t)(x)
$(h ⋅ t)(x) = (4x - 5)(2x + 4) \\ (h ⋅ t)(x) = 4x(2x + 4) - 5(2x + 4) \\ (h ⋅ t)(x) = 8 {x}^{2} + 16x - 10x - 20 \\ (h ⋅ t)(x) = 8 {x}^{2} + 6x - 20$
Part C: Finding h[t(x)]
$h[t(x)] = 4 \times t(x) - 5 \\ h[t(x)] = 4(2x + 4) - 5 \\ h[t(x)] = 8x + 16 - 5 \\ h[t(x)] = 8x + 11$

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what is the y-intercept of the line perpendicular to the line y=-3/4x+5 that includes the point (-3,-3)?

Deffense [45]

Answer:

Step-by-step explanation:

For this question, your friend is the point-slope form.

Point-slope form = $y-y_1 = m(x-x_1)$

The only variables you replace are m = slope, y1 = y of a given point, and x1 = x of a given point.

First, we need to find the slope that is perpendicular to the equation $y=-\frac{3}{4}x+5$

An equation that is perpendicular to another equation have to be negative reciprocals (negative inverse) of each other.

If the slope is 3, then the negative reciprocal of 3 is $-\frac{1}{3}$ .

So, since the given slope is -3/4, the negative reciprocal is $\frac{4}{3}$ .

We will use the negative reciprocal as m since we are trying to find the equation of line that includes (-3, -3) and is perpendicular to the other equation.

We will use point slope form using the (-3, -3) points and negative reciprocal as m.

$y-y_1 = m(x-x_1)\\y-(-3) = \frac{4}{3} (x-(-3))\\y+3=\frac{4}{3}(x+3)$

Now, we need to convert this into slope-intercept form. The reason why we need to do this is because y = mx + b, where b is the y-intercept. To do this, solve for y - or in other words, isolate y..

$y+3=\frac{4}{3}(x+3)\\y+3=\frac{4x}{3}+4\\y+3-3=\frac{4x}{3}+4-3\\y=\frac{4}{3}x+1$

The y-intercept of the line is 1.

3 0

3 years ago

Help me please please

harina [27]

Answer:

$EH = \sqrt{HG^2+EG^2} = \sqrt{4^2+6^2} = \sqrt{16+36} = \sqrt{52} = 2\sqrt{13}$

EG² = GH*GF
EG² = 4*12
EG² = 48
EG = √48 = 4√3

3 0

3 years ago

Johanna wrote the system of equations. 4 x - 3 y = 1, 5 x + 4 y = 9. If the second equation is multiplied by 4, what should the

polet [3.4K]

Answer:

The first equation must be multiplied by -5 to eliminate x variable by addition

Step-by-step explanation:

4 x - 3 y = 1 (1)

5 x + 4 y = 9 (2)

If the second equation is multiplied by 4

5x+4y=9. ×4

We have,

20x+16y=36 (3)

The first equation should be multiplied by -5 to eliminate x variable by addition

4x-3y=1 × -5

We have

-20x+15y=-5 (4)

Add equation (3) and (4) to eliminate x variable

20x+16y=36

-20x+15y=-5

31y=31

Divide both sides by 31

y=1

Substitute y=1 into equation (1)

4 x - 3 y = 1

4x-3(1)=1

4x-3=1

4x=1+3

4x=4

Divide both sides by 4

x=1

4 0

3 years ago

Read 2 more answers

If the diameter of the circle is above 20mm what is the area

Phoenix [80]

Answer:

The area would be 314.16 mm squared

7 0

3 years ago

If $20.18 Pesos is equal to $1 US dollar, tell me how much money Mr. P would have left if he had $100 US Dollars but spent $918

frozen [14]

Answer:

Conversion rates US Dollar / Mexican Peso

10 USD 209.37500 MXN

20 USD 418.75000 MXN

50 USD 1046.87500 MXN

100 USD 2093.75000 MXN

7 0

3 years ago