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3 years ago

15

How to do this problem it dosent make sense

1 answer:

levacccp [35]3 years ago

6 0

Well with those sorts of things, there are online tools you can use. I used one from the explore learning website
Pick the rotate around origin operation, simplify the -80 to a -16 and the 45 to a 9, then take those values and place your point on the graph. Adjust the rotation tool to 90 degrees, and your new point should be on -9, -16. Multiply both numbers by 5 and your answer would be -45, -80.

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Find the equation of a line parallel to y - 5 = 6x - 10 that passes through the point (4, 10). (answer in slope-intercept form)

ANEK [815]

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$\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond$

Find the equation of a line parallel to y-5=6x-10 that passes through (4,10)

$\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}\diamond$

❖ If lines are parallel to each other, they have the same slope.

So the slope of the line parallel to y-5=6x-10 is 6.

Now, since we're also given the point crossed by the line, we write the equation in point-slope form:-

$\sf{y-y_1=m(x-x_1)}$

Substitute 10 for y₁, 6 for m and 4 for x₁:-

$\sf{y-10=6(x-4)}$

On simplification,

$\sf{y-10=6x-24}$

Adding 10 to both sides results in:-

$\sf{y=6x-14}$

So we conclude that Option A is correct.

<h3>Good luck.</h3>

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2 years ago

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3 years ago

lys-0071 [83]

Answer:

$46.2^o$

Step-by-step explanation:

<u><em>The correct question is</em></u>

If b = 9 and c = 13, what is the measure of ∠A? (round to the nearest tenth of a degree)

The picture in the attached figure

we know that

In the right triangle ABC

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substitute the given values

$cos(A)=\frac{9}{13}$

using a calculator

$A=cos^{-1}(\frac{9}{13})=46.2^o$

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