Answer:
Part A: m+1.37=7.9
Part B: 6.53 miles are left to be repaired.
Step-by-step explanation:
Given,
Length of repaired part = 1.37 miles
Total length to be repaired = 7.9 miles
Miles left to be repaired = m
Part A:
Create an equation to show the relationship between the number of miles repaired and the number of miles left to be repaired, m.
Miles left to be repaired + Length of repaired part = Total length to be repaired
m+1.37=7.9
Part B
How many miles are left to be repaired?
Subtracting 1.37 from both sides
6.53 miles are left to be repaired.
Keywords: length, subtraction
Step-by-step explanation:
Answer:
1. 195=6.50·c
2. 30
Step-by-step explanation:
195=6.5·c
Divide both sides by 6.5
30=c
Answer:
3.762 x 10^-7
Step-by-step explanation:
Alright this has the same exact concept as other scientific notation problems.
First, multiply your first numbers: 4.18 x 9 = 37.62
Next, we add our powers together -4 +-4 = -8 (can also be read as -4 - 4 = -8)
We now have 37.62 x 10^-8
Wait! This isn't in scientific notation.
Taking a closer look at this we see 37.62 x 10^-8 can be adjusted by moving the decimal over to the left. Scientific notation must be in simplest form with only one number on the left of the decimal. This gives up 3.762.
Now we need to adjust our notation. Since we moved the decimal over one we are adding one more power to our problem.
Our current power of -8 is now adding a power due to moving the decimal place over one unit to the left. This is equivalent to saying -8 + 1 which equals -7. Now that we fixed our powers, we can put our equation back together for our final answer
3.762 x 10^-7
The correct answer would be letter C. She needs to either break or tie the record. The less than or equal to symbol in the original inequality would be her scoring less or tying the record. Using the greater than or equal to sign would represent her breaking the record or tying with it. Hope this helped.
F(1) = (1)^3 + 2(1)^2 - 5(1) - 6 = 1 + 2 - 5 - 6 = -8; x = 1 is not a solution to the polynomial.
f(-1) = (-1)^3 + 2(-1)^2 - 5(-1) - 6 = -1 + 2 + 5 - 6 = 0; x = -1 is a solution to polynomial.
From the options, a or c has x = -1, both has x = , so lets check for x = 3
f(3) = (3)^3 + 2(3)^2 - 5(3) - 6 = 27 + 18 - 15 - 6 = 24; x = 3 is not a solution to the polynomial.
Therefore the solutions to the polynomial are x = -3, x = -1, x = 2
