B I’m pretty sure okay bye
<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,

0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
Answer: x=100$
Step-by-step explanation:
use the slope formula
y=mx+b
plug in what you have
y=2400, m=22.50x, b=150
solve for x
2400=22.50x+150
subtract 150 from both sides
2250=22.50x
divide 22.50 x from both sides
x=100 people
don't forget your units :)
Answer:
45
Step-by-step explanation:
the left and right side are symetrical
Answer:
F = $13,802.31
she can finance $13,802.31 with this loan.
Step-by-step explanation:
Given;
Rate r = 7% = 0.07
Time t = 4 years
Payment per month MP = $250
Number of months per year n = 12
This can be solved using compound interest for future value series formula;
F = future value
F = MP(((1 + r/n)^(nt) - 1)/(r/n))
Substituting the given values, we have;
F = $250(((1 + 0.07/12)^(12×4) - 1)/(0.07/12))
F = $13,802.31