Solve the system of equation below by graphing them y= 2x-3 y=-2x+5
1 answer:
You might be interested in
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
Answer:
A)
Step-by-step explanation:
Use the two-points formula for the slope of a line.
We know that the points (2,-2) and (9,3) are on the line. If (a,b),(c,d) are points on a line then the slope m is defined by the equation . In this case, a=2,b=-2,c=9 and d=3 then the slope is
.