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lara [203]
3 years ago
15

Segment BC is a midsegment of triangle TUV. What is the length of segment VC? (A)a (B)2b (C)b (D)c

Mathematics
1 answer:
Ganezh [65]3 years ago
7 0
It would be twice whatever the midsegment equals.
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Trey recorded the number of ounces of water he drank each day in the histogram below. Which of the following would be the best m
Anna11 [10]

I believe it's mean absolute deviation

Step-by-step explanation:

6 0
2 years ago
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X 0 2 10 20
prisoha [69]


Use two points from the graph to check if they are constant. In this case let’s use (0,50) & (2,58)

To find slope you have to do the following.

y2-y1 / x2-x1

Plug in the values, 58-50/2-0
This gives you 4.

When you use two other points, in this case (10,90) (20,130) you get a slope of 4.

This means the slope is 4.

We are trying to get an equation of y=mx+b.
We have slope already which is 4. So now we plug in y=4x + b

Now we need to find b. There is an equation to solve for b. Which is b=y1-m(x1)

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8 0
3 years ago
40% of the students in Jody's class
77julia77 [94]
40% = 40/100 = 0.40
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7 0
3 years ago
Pls help in a middle of an exam
KIM [24]

Answer:

\frac{2x^2+4x-9}{(2x-3)(2x+3)(x-1)}

Step-by-step explanation:

\frac{2x}{4x^2-9} + \frac{3}{2x^2+x-3} can be simplified to:
\frac{2x}{(2x-3)(2x+3)}+\frac{3}{(2x+3)(x-1)}

Make them have common denominators so:
\frac{(2x)(x-1) +3(2x-3)}{(2x-3)(2x+3)(x-1)}

Simplify:
\frac{2x^2-2x+6x-9}{(2x-3)(2x+3)(x-1)} = \frac{2x^2+4x-9}{(2x-3)(2x+3)(x-1)}

I don't think you can simplify that fraction further so that's the answer.

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2 years ago
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VMariaS [17]
ASA postulate because theres two angles and the side in the middle
3 0
3 years ago
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