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3 years ago

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Melissa used 4 cups of sugar to bake 54 cookies. If she’s only used 1 cup of sugar, what would be an equivalent ratio of cups to

cookies

1 answer:

daser333 [38]3 years ago

3 0

Answer:

$\frac{2}{27}$

Step-by-step explanation:

We have given that melissa used 4 cups of sugar to bake 54 cookies.

That means 1 cup of sugar will be used to bake $\frac{54}{4}=\frac{27}{2}$ by unitary method

We have to find the ratio of cups to the cookies

We are using 1 cup of sugar

And cookies will be $\frac{27}{2}$

$\text{equivalent ratio}=\frac{1}{\frac{27}{2}}=\frac{2}{27}$

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Murrr4er [49]

Yes they should reach the 8.1 mile marker by noon
2 hours equals 6 miles 2.4+6=8.4
if they kept walking for a full 2 hours they would reach the 8.4 mile marker

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3 years ago

The buyer for a chain of stores purchased lawn ornaments in bulk, paying $23 each. The stores will sell each lawn ornament for $

Naya [18.7K]

Answer:

The markup percentage is 61.2

Step-by-step explanation:

Given as :

The cost price of each ornaments = $23

The sell price of each ornament = $37.08

Let The markup percentage = x

<u>Now, According to question</u>

Markup percentage = $\dfrac{s.p - c.p}{c.p}$ × 100

Or, x% = $\dfrac{37.08 - 23}{23}$

Or, x% = $\dfrac{14.08}{23}$

Or, x% = 0.612

∴ x = 0.612 × 100

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So, The The markup percentage = x = 61.2

Hence, The markup percentage is 61.2 Answer

8 0

3 years ago

I need help please

bija089 [108]

Hey There!

Lets Just Work through your answers,

ⓧ A - An isosceles triangle is a triangle with (at least) two equal sides, so this would not apply to the given triangle.

:) B - A scalene triangle is a triangle in which all three sides have different lengths so this applies to the given triangle. One side measures 10, one measures 11, and one measures 12.1

ⓧ C - A right triangle is a type of triangle that has one angle that measures 90 degrees, which this triangle does not so this does not apply.

ⓧ D - In geometry, an equilateral triangle is a triangle in which all three sides are equal, so this does not apply to the given triangle.

ⓧ E - An obtuse triangle is a triangle with one obtuse angle (greater than 90°) and two acute angles, so this does not apply to the given triangle.

:) F - An acute triangle (or acute-angled triangle) is a triangle with three acute angles less than 90 degrees. So this applies to the given triangle.

In Summary, B & F classify the given triangle correctly.

If you could rate five starts & give brainliest that would be greatly appreciated!

Hope I helped, Have a good day.

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3 years ago

What will it cost to carpet a rectangular floor measuring 9 feet by 21 feet if the carpet costs $30.82 per square yard?

Gre4nikov [31]

answer is $5,824.98

Step-by-step explanation:

I am 90% sure

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3 years ago

In a random sample of 75 American women age 18 to 30, 26 agreed with the statement that a woman should have the right to a legal

ddd [48]

Answer:

a) $z=\frac{0.347-0.328}{\sqrt{0.338(1-0.338)(\frac{1}{75}+\frac{1}{64})}}=0.236$

$p_v =2*P(Z>0.236)=0.813$

If we compare the p value and using any significance level for example $\alpha=0.01$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant differences between the two proportions.

b) We are confident at 99% that the difference between the two proportions is between $-0.188 \leq p_B -p_A \leq 0.226$

Step-by-step explanation:

Previous concepts and data given

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion of women age 18 to 30 agreed with the statement that a woman should have the right to a legal abortion for any reason

$\hat p_A =\frac{26}{75}=0.347$ represent the estimated proportion of women age 18 to 30 agreed with the statement that a woman should have the right to a legal abortion for any reason

$n_A=75$ is the sample size for A

$p_B$ represent the real population proportion for women age 58 to 70 agreed with the statement that a woman should have the right to a legal abortion for any reason

$\hat p_B =\frac{21}{64}=0.328$ represent the estimated proportion of women age 58 to 70 agreed with the statement that a woman should have the right to a legal abortion for any reason

$n_B=64$ is the sample size required for B

$z$ represent the critical value for the margin of error and for the statisitc

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part a

We need to conduct a hypothesis in order to check if the proportion are equal, the system of hypothesis would be:

Null hypothesis: $p_{A} = p_{B}$

Alternative hypothesis: $p_{A} \neq p_{B}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{A}-p_{B}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{A}}+\frac{1}{n_{B}})}}$ (1)

Where $\hat p=\frac{X_{A}+X_{B}}{n_{A}+n_{B}}=\frac{26+21}{75+64}=0.338$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.347-0.328}{\sqrt{0.338(1-0.338)(\frac{1}{75}+\frac{1}{64})}}=0.236$

Statistical decision

Since is a two sided test the p value would be:

$p_v =2*P(Z>0.236)=0.813$

If we compare the p value and using any significance level for example $\alpha=0.01$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant differences between the two proportions.

Part b

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$(0.347-0.328) - 2.58 \sqrt{\frac{0.347(1-0.347)}{75} +\frac{0.328(1-0.328)}{64}}=-0.188$

$(0.347-0.328) + 2.58 \sqrt{\frac{0.347(1-0.347)}{75} +\frac{0.328(1-0.328)}{64}}=0.226$

And the 99% confidence interval for the difference of proportions would be given (-0.188;0.226).

We are confident at 99% that the difference between the two proportions is between $-0.188 \leq p_B -p_A \leq 0.226$

5 0

3 years ago