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Ne4ueva [31]
3 years ago
11

Pls help i will give u brianliest

Mathematics
1 answer:
Fynjy0 [20]3 years ago
7 0

Answer:

Slope = -3

y-intercept = (0,-4)

Equation: y = -3x-4

Step-by-step explanation:

We can take any two input-output pairs from the table to find the equation of given function.

Linear function is given by:

y =mx+b

Here m is the gradient of the functions which is defined as:

m = \frac{rise}{run} = \frac{y_2-y_1}{x_2-x_1}

The input-output pairs are:

(x1,y1) = (-1,-1)

(x2,y2) = (0,-4)

First of all,

m = \frac{-4-(-1)}{0-(-1)}\\= \frac{-4+1}{1} = -3

Putting the value of slope in the equation

y = -3x+b

Putting (-1,-1) in the equation

-1 = -3(-1)+b\\-1 = 3+b\\b = -1-3\\b = -4

The equation will be:

y = -3x-4

Hence,

Slope = -3

y-intercept = (0,-4)

Equation: y = -3x-4

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27 + 71 = 98 + 1 - ______. What should come in the box to make the above number sentence true?
Andreas93 [3]

Answer:

A

Step-by-step explanation:

Read the article and review the phases of mitosis.

Mitosis

What are the four phases of mitosis?

prophase

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cytokinesis

8 0
2 years ago
Find an explicit rule for the nth term of the sequence.
REY [17]

9514 1404 393

Answer:

  (a)  an = -4·2^(n-1)

Step-by-step explanation:

The form for the general term is ...

  an = a1·r^(n-1) . . . . . a1 is the first term; r is the common ratio

For a1=-4 and r=-8/-4 = 2, the rule will be ...

  an = -4·2^(n-1)

8 0
3 years ago
Read 2 more answers
I need to know how to graph this
gladu [14]
It's very simple. Since it gives u the slope, you go up 3 over 1.
6 0
3 years ago
4. Each pail of plaster covers 90 square feet of ceiling. What is the least number of pails of plaster you would need to buy to
alekssr [168]
Answer d: 3 pails


The area of the ceiling:
A = 142 = 196 f2
We need plaster to cover 196 $2
196: 90 = 2.17778
Answer: We have to buy 3 pails of plaster
7 0
2 years ago
Read 2 more answers
What is the next step for x2-6x+9=-1+9
Ede4ka [16]
X^2 - 6x + 9 = -1 + 9. We need to solve for x.
First, add one on each side of the equation:
x^2 - 6x + 9 + 1 = -1 + 9 + 1
x^2 - 6x + 10 = 9
Then subtract 9 from each side:
x^2 - 6x + 10 - 9 = 9-9
x^2 - 6x + 1 = 0
Now we got an equation = 0. This an equation from the second degree, it represented by a parabola which turns up since a>0.
This equation is the developed form as ax^2 + bx + c with a=1; b = -6; and c=1.
Now, to find the zeroes of this equation, we need to find delta Δ.
Δ = b^2 - 4ac.
If Δ>0, the equation admits 2 zeroes: x=(-b-√Δ)/2a and x = (-b+√Δ)/2a.
If Δ<0, the equation doesn't admits any zero.
If Δ=0, the equation admits one zero x = -b/2a

Δ = (-6)^2 - 4(1)(1)
Δ = 36 - 4
Δ = 32
Δ>0
So the zeroes of the equation are:
x = (-b-√Δ)/2a = (6-4√2)/2
x = (-b+√Δ)/2a = (6+4√2)/2

Hope this Helps! :)
7 0
3 years ago
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