Answer:
ntersecting lines DA and CE.
To find:
Each pair of adjacent angles and vertical angles.
Solution:
Adjacent angles are in the same straight line.
Pair of adjacent angles:
(1) ∠EBD and ∠DBC
(2) ∠DBC and ∠CBA
(3) ∠CBA and ∠ABE
(4) ∠ABE and ∠EBD
Vertical angles are opposite angles in the same vertex.
Pair of vertical angles:
(1) ∠EBD and ∠CBA
(2) ∠DBC and ∠EBA
S (3, 0)
C (5, 1)
W (4, -4)
Explanation
You take the first number and add 6 to it and you get the new number and then you take the second number and subtract 3 from it
S: -3 + 6 = 3
S- 3 - 3 = 0
C: -1 + 6 = 5
C: 4 - 3 = 1
W: -2 + 6 = 4
W: -1 - 3 = -4
Answer:
eegstecation
Yea YEA
Step-by-step explanation:
Given:
h = high quality bean ; costs 6 per pound
c = cheaper bean ; costs 3.25 per pound
160 pounds of blended coffee beans at 4.97 per pound
h + c = 160
6h + 3.25c = 160(4.97)
6h + 3.25c = 795.20
h = 160 - c
6(160-c) + 3.25c = 795.20
960 - 6c + 3.25c = 795.20
- 2.75c = 795.20 - 960
- 2.75c = -164.80
c = - 164.80 / -2.75
c = 59.92 or 60 pounds
h = 160 - c
h = 160 - 60
h = 100 pounds
Sarah must blend 100 pounds of high quality bean and 60 pounds of cheaper bean.
Answer:
$6062
Step-by-step explanation:
The formula we are given is
![c=120\sqrt[3]{n^2}+1300](https://tex.z-dn.net/?f=c%3D120%5Csqrt%5B3%5D%7Bn%5E2%7D%2B1300)
We will replace n with 250:
![c=120\sqrt[3]{250^2}+1300\\ \\=120\sqrt[3]{62500} +1300\\\\=120(39.685)+1300\\\\=4762.20+1300\\\\=6062.20 \approx 6062](https://tex.z-dn.net/?f=c%3D120%5Csqrt%5B3%5D%7B250%5E2%7D%2B1300%5C%5C%20%5C%5C%3D120%5Csqrt%5B3%5D%7B62500%7D%20%2B1300%5C%5C%5C%5C%3D120%2839.685%29%2B1300%5C%5C%5C%5C%3D4762.20%2B1300%5C%5C%5C%5C%3D6062.20%20%5Capprox%206062)
