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Digiron [165]
3 years ago
10

Add or subtract as indicated

Mathematics
1 answer:
Aliun [14]3 years ago
5 0

Option B: \frac{11x-9}{x^2-1} is the correct answer

Step-by-step explanation:

Given

\frac{5}{x+1} + \frac{6}{x-1} -\frac{10}{x^2-1}

Simplifying x^2-1

x^2-1 = (x+1)(x-1)

So,

\frac{5}{x+1} + \frac{6}{x-1} -\frac{10}{(x+1)(x-1)}\\=\frac{5(x-1)+6(x+1)-10}{(x+1)(x-1)}\\=\frac{5x-5+6x+6-10}{(x+1)(x-1)}\\=\frac{5x+6x-5+6-10}{(x+1)(x-1)}\\=\frac{11x-9}{(x+1)(x-1)}\\=\frac{11x-9}{x^2-1}

Hence,

Option B: \frac{11x-9}{x^2-1} is the correct answer

Keywords: Fractions, polynomials

Learn more about polynomials at:

  • brainly.com/question/4703807
  • brainly.com/question/4703820

#LearnwithBrainly

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WRITING IN MATH
mrs_skeptik [129]
As a waitress, at the end of the night you have to tip 3% (same as 1/33) of your total earnings to the bussers and hosts.

equation:
total earnings (E) times (3% or 1/33)= money tipped to bussers and hosts(T).

E*1/33=T
8 0
3 years ago
The diagonals of kite KITE intersect at point P. If m A. 34°<br> B. 46°<br> C. 68°<br> D. 92°
JulijaS [17]

Answer:

The diagonal of kite intersect at the point p is C. 68°

7 0
3 years ago
HCF(320, x) = 20, LCM(320, x) = 2240, then x =
HACTEHA [7]

Answer:

  140

Step-by-step explanation:

When working HCF and LCM problems, I like to think in terms of this little diagram:

  (a [ b ) c]

It shows me one of the numbers is ab, the other is bc, the HCF is b and the LCM is abc. "a" and "c" must be relatively prime for "b" to be the HCF.

__

Here, we're given ...

  b = 20

  ab = 320

  abc = 2240

Then ...

  c = abc/(ab) = 2240/320 = 7

  x = bc = 20(7) . . . . . . equivalently, x = (abc·b)/(ab) = (2240·20)/320

  x = 140

6 0
3 years ago
Complete the pattern 274÷1=
Orlov [11]
The answer 274 because anything divided by one is itself
5 0
3 years ago
What’s the correct answer for this?
slava [35]

Answer:

1/4

Step-by-step explanation:

Let's denote the probabilities as following:

Probability that a teenager has a sister:

P(A) = 12/28

Probability that a teenager has a brother:

P(B) = 7/28

Probability that a teenager has both a sister and a brother:

P(A⋂B) = 3/28

Probability that a selected teenager has a sister also has a brother, or in other words, he/she has a brother, given he/she had a sister:

P(B|A)

Let's apply the formula of conditional probability to work out P(B|A)

P(B|A) = P(A⋂B)/P(A) = (3/28)/(12/28) = (3*28)/(12*28) = 3/12 = 1/4

=> Option C is correct

Hope this helps!

7 0
3 years ago
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