If we rewrite it as y=mx+d (which can be taken from here from subtracting ax and c from both sides, then dividing b, resulting in y=(-a/b)(x)-c/b. We can then substitute -a/b for m and -c/b for d), if d=0, then we have m as a constant and as we add a specific number to y (that number being m) every time the x value increases by 1, it therefore forms a straight line. If d is not 0, then we simply add d to every single number - this is still a straight line due to that we still add a specific number to y every time x increases by 1 every single time
Answer:
The area of the regular hexagon is 
Step-by-step explanation:
we know that
The area of a regular hexagon can be divided into 6 equilateral triangles
so
step 1
Find the area of one equilateral triangle

we have

----> is the apothem
substitute


step 2
Find the area of 6 equilateral triangles

Answer: There were 40 euros in the drawer at the beginning.
Step-by-step explanation:
When we subtract 6 from 16, we get 10 more ice-creams were sold.
Similarly, we subtract 70 from 120, we get 50 euros was the total selling price of 10 ice-creams.
i.e. Selling price of 1 ice-cream = (50)÷10 =5 euros
Selling price of 6 ice-creams = 6 x 5 = 30 euros
Money in the drawer at the beginning = 70-30 = 40 euros
Hence, there were 40 euros in the drawer at the beginning.
The answer is 77 becuase you have to add all of the sides that are same as the number
Answer:
The correct answer B) The volumes are equal.
Step-by-step explanation:
The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

which when evaluated gives 4pi/3.
Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.