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vitfil [10]
3 years ago
5

Help please !!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
natita [175]3 years ago
4 0

Answer:

Step-by-step explanation:

You're looking for where f(1) exists, not the limit as x approaches 1. So where f(1) exists is where the dark point is, not where the hole is. Therefore, f(1) = -6.

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Which function is quadratic?
PilotLPTM [1.2K]

Answer:

step 1. A, B,D are incorrectly written as these are not all coordinates. they must be written (x, y)

step 2. so the question becomes is C a quadratic

step 3. The x values must be evenly spaced. the x values are evenly spaced by a difference of 4

step 4. write out the y values: -126, -14, 2, 18

step 5. write out the differences: 140, 16, 16

step 6. write out the differences: -124, 0.

step 7. after doing this twice the numbers nust be the same for this to be a quadratic which they aren't

step 8. C is not a quadratic.

8 0
3 years ago
You stand at point C and look at an aquarium tank. Calculate the radius of the aquarium tank.
leonid [27]

Answer:

The radius of the aquarium tank is 8.25\ ft

Step-by-step explanation:

we know that

Applying the Tangent Secant Theorem

DC^{2}=AC*8

we have that

AC=(D+8)\ ft

DC=14\ ft

substitute

14^{2}=(D+8)*8

196=8D+64

Solve for D

8D=196-64

8D=132

D=16.5\ ft

Find the radius

The radius is half the diameter

r=16.5/2=8.25\ ft

3 0
3 years ago
Read 2 more answers
A number (s) is subtracted from seven. When the result is divided by three, the qoutient is two. What is (s)?
Elis [28]
You can form an equation and solve it to find your answer:
(7 - s)/3 = 2
× 3
7 - s = 6
+ s
7 = 6 + s
- 6
s = 1
So your answer is 1, I hope this helps!
7 0
3 years ago
Read 2 more answers
Does anyone knows how to do this? ​
dedylja [7]

Answer:

(a) i) Vector BC = 3/2 a + 5b

ii) Vector AM = 15/4 a + 5/2 b

(b) Vector QP = -15/4 b where k = -15/4

Step-by-step explanation:

* Lets explain how to solve this problem

∵ ABCD is a trapezium

∵ AB // DC

∵ The vector AB = 3a

∵ Vector DC = 3/2 vector AB

∴ Vector DC = 3/2 × 3a = 9/2 a

∵ Vector AD = 5b

(a)

i) ∵ Vector BC = vector BA + vector AD + vector DC

∵ Vector AB = 3a , then vector BA = -3a

∵ Vector AD = 5b , vector DC = 9/2 a

∴ Vector BC = -3a + 5b + 9/2 a = (-3a + 9/2 a) + 5b

∴ Vector BC = 3/2 a + 5b

ii) ∵ Vector AM = vector AB + vector BM

∵ M is the mid-point of BC

∴ Vector BM = 1/2 vector BC

∵ Vector BC = 3/2 a + 5b

∴ Vector BM = 1/2(3/2 a + 5b) = (1/2 × 3/2) a + (1/2 × 5) b

∴ Vector BM = 3/4 a + 5/2 b

∴ Vector AB = 3a

∴ Vector AM = 3a + 3/4 a + 5/2 b = (3a + 3/4 a ) + 5/2 b

∴ Vector AM = 15/4 a + 5/2 b

(2)

∵ 7 DQ = 5 QC ⇒ divide both sides by 7

∴ DQ = 5/7 DC

∴ The line DC = 7 + 5 = 12 parts ⇒ DQ 5 parts and QC 7 parts

∵ DQ = 5/12 DC

∵ Vector DC = 9/2 a

∴ Vector DQ = 5/12 (9/2 a) = 45/24 a ⇒ divide up and down by 3

∴ Vector DQ = 15/8 a

∵ P is the mid point of AM

∴ Vector AP = 1/2(15/4 a + 5/2 b) = (1/2 × 15/4) a + (1/2 × 5/2) b

∴ Vector AP = 15/8 a + 5/4 b

∵ Vector QP = QD + DA + AP

∵ Vector DQ = 15/8 , then vector QD = -15/8 a

∵ Vector AD = 5b , then vector DA = -5b

∴ Vector QP = -15/8 a + -5b + 15/8 a + 5/4 b

∴ Vector QP = (-15/8 a + 15/8 a) + (-5b + 5/4 b)

∴ Vector QP = -15/4 b

∵ -15/4 is constant

∴ Vector QP = k b ⇒ proved

8 0
2 years ago
F(x)=3x + h f(h-1)=5​
Xelga [282]

Answer:  4h - 3

<u>Step-by-step explanation:</u>

replace "x" with "h - 1" and simplify

f(x) = 3x + h

f(h - 1) = 3(h - 1) + h

          = 3h - 3 + h

          = 4h - 3

4 0
3 years ago
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