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4 years ago

PLEASE HELP!! https://pasteboard.co/GVWjxSs.png

1 answer:

5 0

A) f(-4)-f(-5)=-3- (-11)=-3+11=8
f(-2)-f(-3)=13-5= 8
f(0)-f(-1)=29-21= 8
f(2)-f(1)=45-37=8
f(3)-f(2)=53-45=8
all are 8

b) f(-3)-f(-5)= 5- (-11)= 5+11=16
f(-2)-f(-4)=13-(-3)=13+3=16
f(1)- f(-1)=37-21= 16
f(3)-f(1)=53-37=16

c) f(-2)-f(-5)=13-(-11)=13+11=24
f(-1)-f(-4)=21-(-3)=21+3=24
f(0)-f(-3)=29-5=24
f(1)-f(-2)=37-13=24
f(2)-f(-1)=45-21=24

d) The differences have the same ratio.
cause is a linear function f(x)=ax+b
f(x+3)-f(x)=a(x+3)+b-ax-b=ax+3a-ax=3a
f(x+2)-f(x)=2a
f(x+1)-f(x)=a
so it is the same for every x

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Helwp please thank uuu!

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Step-by-step explanation:

<h3>Given,</h3>

GRAM is a parallelogram
m<GMA = 66°
m<GRP = 32°
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<h3>Solutions:</h3>

i) Since,

Angles on the same side of a transversal in a parallelogram, there sum is 180° so,

<RGM + <GMA = 180°

=> <RGM = 180° - <GMA

=> <RGM = 180° - 66°

=> <RGM = 114° (Ans)

ii) Since,

Opposite angles of a diagonal as a transversal (here RM) are equal so,

<GRP = <PMA = 32°

As we have <GMA = 66° so,

=> <GMP = <GMA - <PMA

= 66° - 32°

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iii) Since,

Opposite angles of a parallelogram are equal so,

<RGM = <RAM = 114°

As we have <PAM = 41° so,

=> <GAR = <RAM - <PAM

= 114° - 41°

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iv) Since,

We got <PMA = 32° and <PAM = 41°, so by angle sum property of a triangle PMA,

=> <MPA = 180° - 32° - 41°

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