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Mnenie [13.5K]
3 years ago
12

Can someone help me pls

Mathematics
2 answers:
FrozenT [24]3 years ago
8 0
There are 4 lateral faces that are triangles.  Each triangle is: A = \frac{b  x  h}{2}
A = \frac{16  x  22}{2}
   = 176

There is one base that is a square. A = L x W
A = 16 x 16
   =  256

Surface area = 256 + 4(176)
                     =  256 + 704
                     = 960

Answer: B

Ugo [173]3 years ago
4 0
Same help me you just broke my brain
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The largest number that rounds to 2,500 when rounded to the nearest ten?
Savatey [412]
2504, as 2499 is 5 less, yet rounds to 2.5K. It is the highest possible for rounding to the tens, as 2505 rounds to 2510.
5 0
3 years ago
Read 2 more answers
3. Simplify. *<br> 5m3 + 2m– 7m3 – 8m
Oksanka [162]

Step-by-step explanation:

5m³ + 2m - 7m³ - 8m

= -2m³ -6m

= -2m(m² + 3)

4 0
2 years ago
How many quarts of pure antifreeze must be added to 8 quarts of a 40% antifreeze solution to obtain a 60% antifreeze solution
anyanavicka [17]

Let <em>q</em> be the number of quarts of pure antifreeze that needs to be added to get the desired solution.

8 quarts of 40% solution contains 0.40 × 8 = 3.2 quarts of antifreeze.

The new solution would have a total volume of 8 + <em>q</em> quarts, and it would contain a total amount of 3.2 + <em>q</em> quarts of antifreeze. You want to end up with a concentration of 60% antifreeze, which means

(3.2 + <em>q</em>) / (8 + <em>q</em>) = 0.60

Solve for <em>q</em> :

3.2 + <em>q</em> = 0.60 (8 + <em>q</em>)

3.2 + <em>q</em> = 4.8 + 0.6<em>q</em>

0.4<em>q</em> = 1.6

<em>q</em> = 4

4 0
2 years ago
Find the other endpoint when the midpoint is (-2,-4) and one endpoint is (0.4).​ I will give brainly thing
Harlamova29_29 [7]
(-4,-12) I think brainly plzzzzzz
8 0
3 years ago
Suppose xy=−4 and dy/dt=−3. Find dx/dt when x=−1.
user100 [1]
When x=-1: \quad (-1)y=-4\qquad\to\qquad y=4\)

Ok that gives us a little more information.
If we implicitly differentiate with respect to t, from the very start, then we can apply our product rule, ya?

x'y+xy'=0

The right side is zero, derivative of a constant is zero.
Where x' is dx/dt and y' is dy/dt.

From here, plug in all the stuff you know:
y' = -3
x = -1
y = 4

and solve for x'.

Hope that helps!
4 0
3 years ago
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