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3 years ago

1+1 ......................................................................................

Mathematics

2 answers:

aleksley [76]3 years ago

8 0

Answer:

2...............................................

Zina [86]3 years ago

8 0

The answer is.....................................2

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A scientist measured the growth rate of a bamboo plant at 6 inches in 12 hours. She compared the growth rate of a bamboo plant t

Arturiano [62]

Answer:

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Step-by-step explanation:

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3 years ago

Help meeee with this questionnnnnnnnnn!!!!!!!!!!!!

Dafna1 [17]

Given:

The scale factor between two circles is $\dfrac{2x}{5y}$ .

To find:

The ratio of their areas.

Solution:

We know that, all circles are similar.

The ratio of the areas of similar figures is equal to the ratio of squares of their corresponding sides or equal to the square of ratio of their corresponding sides.

The scale factor is the ratio of the corresponding sides.

Ratio of areas of circles = Square of scale factor between two circles

$\text{Ratio of areas of circles}=\left(\dfrac{2x}{5y}\right)^2$

$\text{Ratio of areas of circles}=\dfrac{(2x)^2}{(5y)^2}$

$\text{Ratio of areas of circles}=\dfrac{4x^2}{25y^2}$

Therefore, the correct option is D.

3 0

3 years ago

Find the midpoint of A and B where A has coordinates (-5, 3)<br> and B has coordinates (3,-1)

yaroslaw [1]

Answer:

(-1, 1)

Step-by-step explanation:

Midpoint formula: (x₁ + x₂/2 , y₁ + y₂/2)

Substitute the values into the formula.

(-5 + 3/2 , 3 - 1/2)

(-2/2 , 2/2)

(-1,1)

Therefore, the midpoint is (-1, 1).

5 0

3 years ago

If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No

Effectus [21]

If A and B are independent, then $P(A\cap B)=P(A)P(B)$ .

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)$

$P(A\cup B)=0.5+0.2-0.5\cdot0.2$

$\boxed{P(A\cup B)=0.6}$

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

$P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)$

$P(A^c\cap B^c)=1-0.6$

$\boxed{P(A^c\cap B^c)=0.4}$

c. DeMorgan's law can be used here too:

$P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)$

$P(A^c\cup B^c)=1-0.5\cdot0.2$

$\boxed{P(A^c\cup B^c)=0.9}$

4 0

2 years ago

Complete the table using the equation w = m + 4

sveticcg [70]

Answer:

5+4 = 9

6+4 = 10

7+4 =11

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers