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max2010maxim [7]
3 years ago
13

QUESTION 2

Mathematics
2 answers:
Arisa [49]3 years ago
7 0
For Question 2 is 11%

And for question 5 is 8. hope i helped you
dalvyx [7]3 years ago
6 0

Question 2 is 11 i am sure

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An absolute value equation that equals 3 and -3
forsale [732]

Answer\sqrt{9}

Step-by-step explanation:

3 0
3 years ago
0.1846 as a fraction
GenaCL600 [577]
0.1846 as a fraction=1846\10000
8 0
3 years ago
How to do this question plz answer me step by step plzz ​
mojhsa [17]

Answer:

Hope it helps U can still ask me if u have confusions

4 0
3 years ago
Read 2 more answers
Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
2 years ago
(3.8 x 10 ^ -6) x (2.37 x 10 ^ -3)<br><br> Enter the answer in science notification
Black_prince [1.1K]

Multiply the coefficients and the powers of 10 with each other:

(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})

The numeric part simply yields

3.8\times2.37 = 9.006

As for the powers of 10, you have to add the exponents, using the rule

a^b \times a^c = a^{b+c}

So, we have

10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}

So, the final answer is

9.006\times 10^{-9}

7 0
3 years ago
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