Let's break this down:
The difference: Something's gotta be subtracted
Twice a number: So 2 times a number, or n
and 3: So we gotta subtract 2n and 3
is 11: The final answer is 11
So altogether is:
2n - 3 = 11
<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187
</span>
about 23 years
</span></span>
4 and 1 over 2 times 2 and 3 over 2
Answer:
B and D
Step-by-step explanation:
Take a look at all the options x=4, 3, 1, 2 > 0
So, we just care about the domain where x>0, which is 
.
Then plug in x we will have the right answer.
