The area of a rectangular field is 2c3 − c2 + 6 square units. If the length of the field is c − 2 units, what is its width? The
width of the field is units. NextReset
1 answer:
Area of the rectangle can be calculated using the following rule:
Area of rectangle = length * width
We are given that:
area = <span>2c^3 − c^2 + 6 square units
length = c - 2 units
Substitute with the givens in the above equation and solve for the width as follows:
</span>Area of rectangle = length * width
2c^3 − c^2 + 6 = (c - 2) * width
width = (2c^3 − c^2 + 6) / (c - 2) units
Doing the long division for this one, we will find that the simplest form will be:
width = 2c^2 + 3c + 6 + [18/(c-2)]
Hope this helps :)
Note: The attached image shows the procedures of the long division for this problem :)
Area of rectangle = length * width
We are given that:
area = <span>2c^3 − c^2 + 6 square units
length = c - 2 units
Substitute with the givens in the above equation and solve for the width as follows:
</span>Area of rectangle = length * width
2c^3 − c^2 + 6 = (c - 2) * width
width = (2c^3 − c^2 + 6) / (c - 2) units
Doing the long division for this one, we will find that the simplest form will be:
width = 2c^2 + 3c + 6 + [18/(c-2)]
Hope this helps :)
Note: The attached image shows the procedures of the long division for this problem :)
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