Research three different distributions of Linux on the Internet. Record where you went to obtain your information. Compare and c
ontrast the different distributions with regard to their strengths and the packages available for each. After you finish, locate and visit two Linux newsgroups. How did you locate them and where did you obtain the information? What are the topics specific to each? Find two questions per newsgroup posted by a user in need of a solution to a problem, and follow the thread of responses suggested by others to solve that problem.
1 answer:
Answer:
The three Linux distributions are Arch Linux, Ubuntu and Fedora. In order to get more detailed information go to the wikipedia page of comparision of linux distributions.
Strengths and Features of these three are attached.
The two linux newsgroups are
1) Comp.os.linux.announce
2)comp.os.linux.networking
Explanation:
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Solution :
#include
#include
#include
//Converts to binary string.
* hexadecimal
Binary(char* hexdec)
{
long = 0;
char *string = (sizeof(char) * 9);
while (hexdec[i]) {
//Simply assign binary string for each hex char.
switch (hexdec[i]) {
strcat(string, "0000");
break;
strcat(string, "0001");
break;
strcat(string, "0010");
break;
strcat(string, "0011");
break;
strcat(string, "0100");
break;
strcat(string, "0101");
break;
strcat(string, "0110");
break;
strcat(string, "0111");
break;
strcat(string, "1000");
break;
strcat(string, "1001");
break;
case 'A':
case 'a':
strcat(string, "1010");
break;
case 'B':
case 'b':
strcat(string, "1011");
break;
case 'C':
case 'c':
strcat(string, "1100");
break;
case 'D':
case 'd':
strcat(string, "1101");
break;
case 'E':
case 'e':
strcat(string, "1110");
break;
case 'F':
case 'f':
strcat(string, "1111");
break;
default:
printf("\nInvalid hexadecimal digit %c",
hexdec[i]);
string="-1" ;
}
i++;
}
return string;
}
int main()
{ //Take 2 strings
char *str1 =hexadecimalToBinary("FA") ;
char *str2 =hexadecimalToBinary("12") ;
//Input 2 numbers p and n.
int p,n;
scanf("%d",&p);
scanf("%d",&n);
//keep j as length of str2
int j=strlen(str2),i;
//Now replace n digits after p of str1
for(i=0;i<n;i++){
str1[p+i]=str2[j-1-i];
}
//Now, i have used c library strtol
long ans = strtol(str1, NULL, 2);
//print result.
printf("%lx",ans);
return 0;
}